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The perimeter of a rectangle is 97m The width is 2m more than half the length Find the length and width?
Let the width be 1/2x+2 and the length be x: 2(width+length) = perimeter 2(1/2x+2+x) = 97m x+4+2x = 97 x+2x = 97-4 3x = 93 x = 31 Therefore: length = 31m and width = 17.5m Check: 31+31+17.5+17.5 = 97m
Length of a box 2x plus 1 width is x. x equals 2.5 What is the surface area?
The answer is 15 like its given (2x+1) length and X is width .whereas X = 2.5 so the surface area of a box is Length X Width. putting the value of X = 2.5 in (2X2.5 +1)(2.5)=15
What is the length and width of a rectangle that has a perimeter of 120 cm and its one fifth as much as the length?
1/5 of 120 = 24 =length and let the width be x: Perimeter = 2(24+x) = 120 48+2x = 120 2x = 120-48 2x = 72 x = 36 Therefore: length = 24 cm and width = 36 cm Check: 24+24+36+36 = 120 cm
What is the length of the rectangle if the perimeter is 134m and the length is 7 more than half the width?
Let the length be (1/2x+7) and the width be x: Perimeter = 2(length+width) = 134 2(1/2x+7+x) = 134 Multiply out the brackets: x+14+2x = 134 Collect like terms and subtract 14 from both sides: 3x = 120 Divide both sides by 3: x = 40 Therefore: length = 27 meters and width = 40 meters Check: 27+27+40+40 = 134 meters
The length of an airport is 1 mile more than twice the width the area is 21 square miles identify the legth and width of the airport?
Let the length be (2x+1) and the width be x: length*width = area (2x+1)*x = 21 square miles 2x2+x-21 = 0 Solving the above quadratic equation works out as: x = -7/2 or x = 3 it must be the latter because dimensions can't be negative. Therefore: length = 7 miles and width = 3 miles
