Let the length be 2x+1 and the width be x:-
And so: (2x+1) times x = 452 or 2x^2 +x -452 = 0
Using the quadratic equation formula x has a positive value of: 14.78537495
Width = 14.78537495 yds and length is 2*(14.78537495)+1 = 30.5707499 yds
Check: width times length = 451.9999998 which rounds to 452 square yards
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
if the width is 3.5 then the length is 10 10 = 3 +2(3.5) 10 x 3.5 = 35
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
twice length + twice width = perimeter In this example, L= 3W 2(3W)+2(W)=64 8W=64 W=6 L =3W L=18 The dimensions of this rectangle are: 18 by 6
The dimensions of the rectangle are 21 units by 9 units
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
The dimensions are 16 units by 8 units of mearsurement
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
It has 2 dimensions which are length and width
2x4
They are also known as the "dimensions" of a rectangle.
4cm by 13cm
9" x 4"
It is: 15 meters by 30 meters