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The perimeter doesn't tell you the dimensions. There are an infinite number
of rectangles with different dimensions that all have the same perimeter.
Here are a few. All of these have perimeters of 200:
1 x 99
2 x 98
3 x 97
4 x 96
5 x 95
6 x 94
.
.
15 x 85
.
.
27 x 73
.
.
39 x 61
.
.
47 x 53
48 x 52
49 x 51
49.1 x 50.9
49.2 x 50.8
49.3 x 50.7
49.4 x 50.6
.
.
etc.
Also, notice that it doesn't necessarily even have to be a rectangle !
.
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∙ 13y ago
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What is the perimeter of 24cm by 100cm?
248cm. Why? Because it is a rectangle so the perimeter is length + length + width + width or just widthx2 + lengthx2. So, 24x2=48 and 100x2=200. 200+48=248cm.
How can you get the width when you have the perimeter and the length?
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
What is one different way to to find the perimeter of a rectangle?
Length + length + width + width = perimeter. Length + width x 2 = perimeter
How do you find the length of a rectangle if the perimeter is 40 and the width is 2inches?
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
How do you find the width of a rectangle if you know the perimeter and the length?
Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length
The perimeter of a rectangle is 200 inches the length exceeds the width by 96 inches?
Length + width = half perimeter = 100". Length is 98", width is 2"
If 2 rectangles have the same area must they have the same perimeter?
Not at all.Rectangle A:-- Length = 20-ft, Width = 10-ft.-- Area = 200 square ft-- Perimeter = 60-ftRectangle B:-- Length = 16-ft, Width = 12.5-ft-- Area = 200 square ft-- Perimeter = 57-ftRectangle C:-- Length = 40-ft, Width = 5-ft-- Area = 200 square ft-- Perimeter = 90-ftRectangle D:-- Length = 50-ft, Width = 4-ft-- Area = 200 square ft-- Perimeter = 108-ftRectangle E:-- Length = 100-ft, Width = 2-ft-- Area = 200 square ft-- Perimeter = 204-ftRectangle F:-- Length = 800-ft, Width = 3 inches-- Area = 200 square ft-- Perimeter = 1600-ft 6-in
How do you get the area if you have the width and the perimeter?
Perimeter = 2 lengths + 2 widths 1/2 perimeter = length + width Length = 1/2 perimeter - width Area = length x width That's (1/2 perimeter - width) x (width) .
How can you get the width when you have the perimeter and the length?
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
If the perimeter is 48 If the length is twic the width what is the length of rectangle?
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
What is one different way to to find the perimeter of a rectangle?
Length + length + width + width = perimeter. Length + width x 2 = perimeter
How do you find the length of a rectangle if the perimeter is 40 and the width is 2inches?
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
How do you find width when you have perimeter and length?
width = (perimeter-2*length)/2
How do you find the width of a rectangle if you know the perimeter and the length?
Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length
How can you calculate the length of a rectangle if the perimeter and the width are given?
Because the perimeter is lenght + length +width +width, you do perimeter - double the width, and then halve the remaining number. that should give you the length.
How do you find the length of a rectangle knowing the perimeter and the width?
You divide the perimeter by the width and you get the lenght
What is an expression for the perimeter of a rectangle that has a length which is seven times its width?
Perimeter = length + length + width + width Let "w" = width, then "7w" must equal the length (because it's 7 times the width) 7w + 7w + w + w = perimeter 16w = perimeter
