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For the general straight line eq'n ; y = mx + c 'm' is the slope 'c' is the y-intercept. For a pair of point on a graph ( x1,y1,) & ( x2,y2) Then m = {y1 - y2) / ( x1 -x2) Note the 'y' co-ords go on the top , and the 'x' co-ods go on the botton. Note also The position of first term '1' and the second '2' term. Otherwise you will have a wrongly calculated slope/gradient.
X = y2 =====
you need 2 points on the line y2-y1 slope=----- x2-x1
Points: (x1, y1) and (x2, y2) Slope: y1-y2/x1-x2
y2 - 64 can be written as y2 - 82, which is of the form of a2 - b2.And a2 - b2 is factored as (a-b)(a+b).Therefore, y2 - 64 is factored as (y+8)(y-8).
Select two points on the graph and suppose their coordinates are (x1, y1) and (x2, y2) then the gradient = (y1 - y2) / (x1 - x2) provided that x1 and x2 are different. If not, the gradient is not defined.
If you want to have an center point of zero you use the equation x2+y2=r2. In this case x2+y2=9.
formula to figure out the rate of change of a line on a graph m= y2-y1/x2-x1
X2+y2=25 (x-8)2+y2 =41
Given two coordinates (x1,y1) and (x2,y2) The midpoint is ( ((x2+x1)/2) , ((y2+y1)/2) )
y2 - 16y + 64 = 0 (y - 8)2 = 0 y - 8 = 0 y = 8
im not sure sure but i think it is squares on paper and a graph then put the information on to it durr.... ;]