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'v' generally refers to final velocity 'u' generally refers to initial velocity (because not everything starts from a motionless state, where 'u' would equal zero) It is better to annotate initial velocity as v0 (v-sub-zero or simply v-zero).
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A equals finial velocity-initial velocity divided by time?
This formula is derived from one of the basic laws of motion; v = u + at : where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration and 't' is the time v = u + at, therefore, v - u = at : a = (v - u) ÷ t
What will be the final velocity if the acceleration of 10 meters per second squared is sustained for 7 seconds?
It will depend upon the initial velocity of the body. If 'u' be the initial velocity of the body, then the final velocity will be: v = u + at (v = final velocity, a = acceleration, t = time) i.e., v=u+10*7 = (u + 70) m/sec. If u=0 (i.e the initial velocity be zero) then final velocity, v=70 m/sec.
How do I calculate acceleration from change in velocity and distance?
change in velocity (v) = acceleration (a) x time (t); distance s = 1/2 a times t squared; solve for time and substitute; find a = v squared /(2s)
How do you develop the general velocity equation from a Velocity vs Time graph?
Derivitives of a velocity : time graph are acceleration and distance travelled. Acceleration = velocity change / time ( slope of the graph ) a = (v - u) / t Distance travelled = average velocity between two time values * time (area under the graph) s = ((v - u) / 2) * t
What is the formula for time when velocity and mass are given?
twice the velocity of the object divided by the supriment weight I have my PhD hope this helps That answer is wrong, or I misunderstand the question. If you have a velocity vs time graph, and the velocity is constant (graph is a horizontal line), then by definition, the change of velocity with respect to time (acceleration) is zero.
How do I rearrange the acceleration formula to solve it for initial velocity?
Where a = (v-u)/t a is acceleration, v is final velocity u is initial velocity t is time so, u=v-at
What is instantaneous velocity in math?
if under uniform acceleration or deceleration v = u + (a*t) where: v = instantaneous velocity u = initial velocity a = acceleration (negative if decelerating) t = time elapsed
A equals finial velocity-initial velocity divided by time?
This formula is derived from one of the basic laws of motion; v = u + at : where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration and 't' is the time v = u + at, therefore, v - u = at : a = (v - u) ÷ t
. ok v velocity a acceleration but what about you?
if by 'you', you mean 'u' then u is the initial velocity v is the final velocity. you need to know the initial velocity in trajectory question (motion of an object through the air) to find height, acceleration, time etc.
What will be the final velocity if the acceleration of 10 meters per second squared is sustained for 7 seconds?
It will depend upon the initial velocity of the body. If 'u' be the initial velocity of the body, then the final velocity will be: v = u + at (v = final velocity, a = acceleration, t = time) i.e., v=u+10*7 = (u + 70) m/sec. If u=0 (i.e the initial velocity be zero) then final velocity, v=70 m/sec.
How do you work out velocity when given acceleration and time?
Answer: v=u + at v (Velocity) = u (Starting velocity) + a (acceleration) x t (time) So, starting from stationary (u=0), the velocity is simply a x t e.g. if the acceleration is 5mph per second per second, after 10 seconds you would be travelling at 50mph. Answer: The above is for constant acceleration. In the case of variable acceleration, integration has to be used.
How is acceleration caculated?
Acceleration is the the fluctuation in velocity per unit time.to calculate the acceleration we need the formula : Acceleration = Velocity fluctuations / time taken or Acceleration = Final velocity - Initial velocity / time taken or a = v-u/t
What is the formula for time if the given is in acceleration and velocity?
You need velocity at two points in time, and the acceleration must be constant. If the initial velocity is u ms-1 and the final velocity is v ms-1, and the time interval is t then t = (v - u)/a s.
How do you get the displacement if the if the final velocity is not given?
Use s=ut+0.5at^2 (^2 notation for squared)Or calculate the final velocity from the known variables (Initial Velocity, Acceleration and Time)v=u+at Where V = Final Velocity, u = Initial Velocity, a = Acceleration, t = TimeThen calculate displacement (s) using s=0.5(u+v)t
What is the formula and units for acceleration?
Acceleration is the rate of change of velocity. Acceleration= Velocity / Time. Three equations of motion can also be used to determine acceleration- 1. v*v= u*u + 2aS 2. S= ut+1/2 at*t 3. v= u+at Unit of acceleration= m/s*s (metre per second square)
How do you compute the formula of acceleration?
a=v-u/t accelleration is velocity minus uniform velocity divided by time
What equation would you use to find the acceleration of an object of known mass if you also know the initial velocity final velocity and time over which the acceleration occured?
Use the equation a=(v-u)/t, whereby v stands for final velocity, u for initial velocity and t for time.
