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x3 - x2 + x - 2 has no rational factors.

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Q: What is x3 - x2 plus x - 2 factored?
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Related questions

What is x3-x2 plus 2x factored?

x3 - x2 + 2x = x*(x2 - x + 2) which cannot be factored further.


What is x3-x2-x minus 2 factored?

x3-x2


What is x3-x2-2x plus 2 factored?

x3 - x2 - 2x +2 you can divide this into two parts for now x3 - x2 and -2x +2 factor out everything you can from both x2(x-1) and -2(x+1) since the insides of the parentheses are the same, we can put them together, then multiply it by the sum of the two parts outside the parentheses. (x-1)(x2-2)


What is the factored answer to x2 plus x-6?

x2+x-6 = (x-2)(x+3) when factored


Factor x3 plus 8?

x3 + 8 = x3 + 23 = (x + 2)[x2 - (x)(2) + 22] = (x + 2) (x2 - 2x + 4)


Factor Completely x3 plus 8?

x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)


Which expression is the factored equivalent of x2 plus 7x - 18?

x2+7x-18 = (x+9)(x-2) when factored


What is the factor of the trinomial -x 3-10xsquare plus 24x?

-x3 -10x2 + 24x 1) -x can be factored out to give, -x(x2 + 10x - 24) 2) The bracketed expression can be factored as (x + 12)(x - 2), which now gives, -x(x + 12)(x - 2) = -x3 -10x2 + 24x


Factor x2-2 plus 4?

x2 - 2 + 4 = x2 + 2This term can not be factored any further


What is x2 plus 5x plus 6 factored out?

x2 + 5x + 6 = (x + 2)(x + 3)


Factor X cubed plus x squared plus 2x plus 2?

Factor x3 + x2 + 2x + 2, by grouping. Group the first two terms and the last two terms. Then factor. First, factor x3 + x2 by pulling out an x2 term: x2(x + 1) Second, factor 2x + 2 by pulling out a 2: 2(x + 1) So, you now have: x2(x + 1) + 2(x + 1) If you have factored correctly, the terms inside the parentheses should be the same. Now regroup. ANS: (x + 1)(x2 + 2)


Write a c plus plus program to find the sum of series S equals 1 plus x2 plus x3 plus x3. plus xn?

(xn+2-1)/(x2-1)