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Q: What is x if negative log x equals 21.1?

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1 x 211, 211 x 1

-log x = 21.1, x > 0 log x = -21.1 x = 10-21.1 x = 1/1021.1 x = 7.94328235 x 10-22

2 log(x) = log(8)log(x2) = log(8)x2 = 8x = sqrt(8) = 2.82843 (rounded)Note that only the positive square root of 8 can serve as a solution to thegiven equation, since there's no such thing as the log of a negative number.

If the log of x equals -3 then x = 10-3 or 0.001or 1/1000.

the value of log (log4(log4x)))=1 then x=

y = 10 y = log x (the base of the log is 10, common logarithm) 10 = log x so that, 10^10 = x 10,000,000,000 = x

log x = -4 => x = 10-4 = 0.0001

log(x) = 3x = 10log(x) = 103 = 1,000

log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1

0.4772

It is negative.

log x2 = 2 is the same as 2 log x = 2 (from the properties of logarithms), and this is true for x = 10, because log x2 = 2 2 log x = 2 log x = 1 log10 x = 1 x = 101 x = 10 (check)

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