Best Answer

2 log(x) = log(8)

log(x2) = log(8)

x2 = 8

x = sqrt(8) = 2.82843 (rounded)

Note that only the positive square root of 8 can serve as a solution to the

given equation, since there's no such thing as the log of a negative number.

Q: What does x equals in 2 log x equals log 8?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1

x = 2, y = 84x + 8y= 4(2) + 8(8)= 8 + 64= 72

X = 2, 2 X 2 X 2 = 8 - 8 = 0

the value of log (log4(log4x)))=1 then x=

2 x 2 x 2 = 8

Related questions

log x2 = 2 is the same as 2 log x = 2 (from the properties of logarithms), and this is true for x = 10, because log x2 = 2 2 log x = 2 log x = 1 log10 x = 1 x = 101 x = 10 (check)

log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1

x = 3*log8 = log(83) = log(512) = 2.7093 (approx)

G(x) = log(2x) + 2, obviously!

log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09

log(x)+log(8)=1 log(8x)=1 8x=e x=e/8 You're welcome. e is the irrational number 2.7....... Often log refers to base 10 and ln refers to base e, so the answer could be x=10/8

11

When the logarithm is taken of any number to a power the result is that power times the log of the number; so taking logs of both sides gives: e^x = 2 → log(e^x) = log 2 → x log e = log 2 Dividing both sides by log e gives: x = (log 2)/(log e) The value of the logarithm of the base when taken to that base is 1. The logarithms can be taken to any base you like, however, if the base is e (natural logs, written as ln), then ln e = 1 which gives x = (ln 2)/1 = ln 2 This is in fact the definition of a logarithm: the logarithm to a specific base of a number is the power of the base which equals that number. In this case ln 2 is the number x such that e^x = 2. ---------------------------------------------------- This also means that you can calculate logs to any base if you can find logs to a specific base: log (b^x) = y → x log b = log y → x = (log y)/(log b) In other words, the log of a number to a given base, is the log of that number using any [second] base you like divided by the log of the base to the same [second] base. eg log₂ 8 = ln 8 / ln 2 = 2.7094... / 0.6931... = 3 since log₂ 8 = 3 it means 2³ = 8 (which is true).

log9(x)=2 x=9^2 x=81

[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5

X is the log(to the base 2) of 10 = 3.324(rounded)

2*log(15) = log(x) 152 = x; its equivalent logarithmic form is 2 = log15 x (exponents are logarithms) then, it is equivalent to 2log 15 = log x, equivalent to log 152 = log x (the power rule), ... 2 = log15 x 2 = log x/log 15 (using the change-base property) 2log 15 = log x Thus, we can say that 152 = x is equivalent to 2*log(15) = log(x) (equivalents to equivalents are equivalent)