To convert a quadratic equation from vertex form, (y = a(x - h)^2 + k), to standard form, (y = ax^2 + bx + c), you need to expand the equation. Start by squaring the binomial: ( (x - h)^2 = x^2 - 2hx + h^2 ). Then, multiply by (a) and add (k) to obtain (y = ax^2 - 2ahx + (ah^2 + k)), where (b = -2ah) and (c = ah^2 + k). This results in the standard form of the quadratic equation.
Ax + By = C By = -Ax + C y = (-A/B)x + C/B
a function
Ax + By = CSubtract 'Ax' from each side:By = -Ax + CDivide each side by 'B' :y = -(A/B)x + C/BThe slope of the line is -(A/B) .The y-intercept is (C/B) .
a(x + y - z)
a(x + y + z)
To convert a quadratic equation from vertex form, (y = a(x - h)^2 + k), to standard form, (y = ax^2 + bx + c), you need to expand the equation. Start by squaring the binomial: ( (x - h)^2 = x^2 - 2hx + h^2 ). Then, multiply by (a) and add (k) to obtain (y = ax^2 - 2ahx + (ah^2 + k)), where (b = -2ah) and (c = ah^2 + k). This results in the standard form of the quadratic equation.
Ax + By = C By = -Ax + C y = (-A/B)x + C/B
a function
ax + ay - AZ = a(x + y - z)
Ax + By = CSubtract 'Ax' from each side:By = -Ax + CDivide each side by 'B' :y = -(A/B)x + C/BThe slope of the line is -(A/B) .The y-intercept is (C/B) .
y - 8 = x^2 + 12x + 36 y - 8 = (x + 6)^2 y = (x + 6)^2 + 8 or f(x) = (x + 6)^2 + 8 So -h = 6 so that h = -6, and k = 8
Using the distance formula it is the square root of: (h-x)^2 +(k-y)^2
ax + by + cz + ... = k where x, y, z, etc are variables and a, b, c etc and k are constants. In the simple case of 2 variables, this becomes ax + by = k which can be rewritten as y = mx + c (different c from the first equation above).
a(x + y - z)
y=ax y'=ln(a)*ax
k = 0.1