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y - 8 = x^2 + 12x + 36

y - 8 = (x + 6)^2

y = (x + 6)^2 + 8

or f(x) = (x + 6)^2 + 8

So -h = 6 so that h = -6, and k = 8

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Q: Put the equation y minus 8 equals x squared plus 12 x plus 36 in vertex form f left paren x right paren equals a left paren x minus h right paren squared plus k and find values for a h and k?
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