x^8 - y^8 = (x - y)(x + y)(x^2 + y^2)(x^4 + y^4)
x + y = 10 y = x + 8 so, x + (x + 8) = 10 2x + 8 = 10 2x + 8 - 8 = 10 - 8 2x = 2 x = 1 and y = 9 because y = x + 8 y = 1 + 8 y = 9
If you mean: y = x+4 and y = 3x+8 then x = -2 and y = 2
x + y = 10 y = x + 8 so, x + (x + 8) = 10 2x + 8 = 10 2x + 8 - 8 = 10 - 8 2x = 2 x = 1 and y = 9 because y = x + 8 y = 1 + 8 y = 9
This question equates to, find x and y such that x + y = 8 x - y = 8 Solving the second equation for x: x = 8 + y Substituting in to the first equation: 8 + y + y = 8 2y = 0 y = 0 Solving for x: x - 0 = 8 x = 8. The two numbers are 8 and 0.
If x + y = 10 and y = x + 8Substitute y = x + 8 into x + y = 10Which gives; x + x + 8 = 10So; 2x + 8 = 10( - 8 from both sides); 2x=2So: x =1. Substitute back into y = x + 8And therefore y = 1 + 8 ; y=9
x+y=8 y=-x+8 is not an inverse variation. However, y=8/x is an inverse variation or y varies inversely as x.
-x+ 4y>-8, x+y≤3 y≤3-x -x+4(3-x)>-8 -x+12-4x>-8 12-5x>-8 -5x>-20 x>4 y≤3-(4) y≤-1
y=x+8 is a linear equation. Y is the Y point on a graph, X is the slope, and 8 is the y intercept
14
Let this numbers be x and y, then x + y = 52 x - y = 8 x = 8 + y x + y = 52 substitute 8 + y for x into the first equation; 8 + y + y = 52 8 + 2y = 52 subtract 8 to both sides; 2y = 44 divide by 2 to both sides; y = 22 x = 8 + y substitute 22 for y into the equation; x = 8 + 22 x = 30 Thus this numbers are 22 and 30. 22 & 30
x+y=-8 2x-y=4 y=-x-8 2x+x+8=4 3x=-4 x=-4/3 -4/3 + y= -8 y = -8 + 4/3 y= -6 2/3