Q: What largest number of five digits is divisible by 99 Give Explanations?

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The largest 5-digit number divisible exactly by 99 is 99990.

995 is divisible by 5 evenly and is the largest 3 digit number to satisfy the condition

A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.

The largest number with 5 digits is 9999999999/14=7142.785714285714 take all the nos before the decimal point 7142 * 14 = 99988 so 99988 is the largest number with 5 digits that is divisible by 14.

99990

A number is divisible by 3 if the sum of its digits is divisible by 3.

If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.

A number is divisible by 9 if the sum of its digits is divisible by 9. Thus, the number 99999 is divisible by 9 (the sum of its digits is 45, and it is clearly 11111 * 9), and because 99999 is the largest 5 digit number, it must be the largest 5 digit multiple of 9. 99999 is the greatest no divisible by 9.if u divide it u`ll get 11111.

-11

Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.

A number is divisible by 4 if the number formed by its last two digits is divisible by 4.Equivalently, halve the number formed by the last two digits. If the quotient is even, then the original number is divisible by 4.

972.

99

999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.

If the last 3 digits are divisible by 8, the number is divisible by 8.

Yes.

4

If the last two digits of a number are divisible by four, the whole number is divisible by four.

9

9

If the sum of the digits of a number is divisible by 3 ,then the number is divisible by 3.. is 36 is right

Add all the digits of the number together - if the sum of the digits is divisible by 9, then the original number is too.

If sum of digits of a number is divisible by 3 then the number is divisible by 3. Sum of digits = 5+1+8 = 14 and 14 is not divisible by 3. So 518 is not divisible by 3.

Yes it is. In order for it to be divisible by 9, the sum of the digits in the number must also be divisible by 9. In this case - the sum of the digits is 27.

If the last two digits of a number are divisible by 4, the whole number is divisible by 4.