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It is 8961 - W*int(8961/W)
Nope - For any number to be divisible by three, the sum of the digits added together must ALSO be divisible by three. In this case 1+4=5.
342 is divisible by 6 and not 5.Numbers divisible by 5 end in zeros or fivesNumbers divisible by 6 have a slightly more complicated rule. If, when the individual digits are added together and they make a multiple of 3, see if the number is even. If so, and the digits add up to a multiple of 3, then the number is a divisible by 6.
14
13533/31 = 436 quotient and 17 remainder 436*31=13516 436*32=13547 13533+14=13547 14 is to be added
339 + 1 = 340,which is exactly divisible.
It is 20 because 5220/180 = 29
It is 8961 - W*int(8961/W)
9400÷65 gives144 quotient,40 remainder. 65×145 =9425 25 is the least
10056÷23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor× quotient so 10056-5=23×437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23×438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23
Any number ending in 3.
3500/42 give 83 quotient,14 remainder next possibility 42*84 =3528. 28 must be added to 3500 then only it will divisible by 42.now check the dividend 3528 with the following divisor 49,56,63 3528/49=72 divisible 3528/56=63 divisible 3528/63=56 divisible So 3528 is divisible by 42,49,63,56 So 28 must be added 28 is the
Nope - 1038 is an even number and thus is divisible by 2. Its digits added together total 12 - which is divisible by 3... therefore the original number is also divisible by 3 !!
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
459684/187 give 2458 and 38 as quotient and remainder. Now next possibility 187 *2459 give 459833. 459833-459684 =149 it should be added. 149 is answer
Seven
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).