Want this question answered?
first, what is x?
It is 1 so that 7310 is divisible by 5 or 10
NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible
A number is divisible by 234 if:its last digit is 0, 2, 4, 6 or 8; andthe sum of its digits (the calculation repeated if required), is divisible by 9; andthe result of nine times the last digit subtracted from the number formed by the rest (the calculation repeated if required) is divisible by 13.
-7754
first, what is x?
It is 1 so that 7310 is divisible by 5 or 10
NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible
When a positive number is subtracted from zero the result is a negative number.
The number is two
Yes, 79002 is exactly divisible by 6; the result is 13167.
7 subtracted from the quotient of a number and 2 is a -6
9
The number is 5.
When one number is subtracted from another number, the result is known as the difference.
2 or -1
-7754