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Q: What least number should be subtracted from 789 so that the result is exactly divisible by 56?

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first, what is x?

It is 1 so that 7310 is divisible by 5 or 10

NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible

-7754

A number is divisible by 234 if:its last digit is 0, 2, 4, 6 or 8; andthe sum of its digits (the calculation repeated if required), is divisible by 9; andthe result of nine times the last digit subtracted from the number formed by the rest (the calculation repeated if required) is divisible by 13.

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first, what is x?

316548/375 =844 quotient,48 remainder Dividend- remainder=divisor *quotient 316548-48=375*844 which gives 316500. Compare both that is 316548 and 316500 difference is 48. 48 is to be subracted.

It is 1 so that 7310 is divisible by 5 or 10

NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible

When a positive number is subtracted from zero the result is a negative number.

316548÷365 give 867 quotient 93 remainder Dividend-remainder= divisor*quotient 316548-93=365*867 which is 316455 93 should be subracted.

The number is two

Yes, 79002 is exactly divisible by 6; the result is 13167.

7 subtracted from the quotient of a number and 2 is a -6

9

The number is 5.

When one number is subtracted from another number, the result is known as the difference.