first, what is x?
NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible
It is 1 because 734688/3 = 244896
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
20
To find the least number that must be added to 37969 to make it exactly divisible by 65, first, we calculate the remainder when 37969 is divided by 65. The remainder is 44 (since 37969 ÷ 65 = 584 with a remainder of 44). To make it divisible by 65, we need to add (65 - 44 = 21). Thus, the least number that must be added is 21.
18 must be subtracted from 5694 to get a number exactly divisible by 43
The multiple of 65 immediately less than 9400 is 9360. Therefore 40 has to be subtracted.
NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible
13801-55 = 13746 and 13746/87 = 158
The answer is 48illustration:833 is a multiple of 49 which is more than 832the multiple which is immediately less than 833 is 784so the difference that must be subtracted is 832- 784 = 48
what least number must be subtracted from 13081 to get a number exactly divisible by 87
339 + 1 = 340,which is exactly divisible.
It is 1 because 734688/3 = 244896
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
6
20
No. In order for a number to be exactly divisible by 3, the digits in the number must also be divisible by three. In this example, 9+5+5=19.