first, what is x?
It is 1 so that 7310 is divisible by 5 or 10
NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible
A number is divisible by 234 if:its last digit is 0, 2, 4, 6 or 8; andthe sum of its digits (the calculation repeated if required), is divisible by 9; andthe result of nine times the last digit subtracted from the number formed by the rest (the calculation repeated if required) is divisible by 13.
-7754
first, what is x?
It is 1 so that 7310 is divisible by 5 or 10
NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible
When a positive number is subtracted from zero the result is a negative number.
The number is two
Yes, 79002 is exactly divisible by 6; the result is 13167.
7 subtracted from the quotient of a number and 2 is a -6
9
A number is divisible by 234 if:its last digit is 0, 2, 4, 6 or 8; andthe sum of its digits (the calculation repeated if required), is divisible by 9; andthe result of nine times the last digit subtracted from the number formed by the rest (the calculation repeated if required) is divisible by 13.
The number is 5.
When one number is subtracted from another number, the result is known as the difference.
-7754