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∙ 11y agoWant this question answered?
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first, what is x?
It is 1 so that 7310 is divisible by 5 or 10
NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible
A number is divisible by 234 if:its last digit is 0, 2, 4, 6 or 8; andthe sum of its digits (the calculation repeated if required), is divisible by 9; andthe result of nine times the last digit subtracted from the number formed by the rest (the calculation repeated if required) is divisible by 13.
-7754
first, what is x?
It is 1 so that 7310 is divisible by 5 or 10
NOT CALCULUS. Use long division. 2x2 + x - 1(4x^4) 2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible
When a positive number is subtracted from zero the result is a negative number.
The number is two
7 subtracted from the quotient of a number and 2 is a -6
Yes, 79002 is exactly divisible by 6; the result is 13167.
9
A number is divisible by 234 if:its last digit is 0, 2, 4, 6 or 8; andthe sum of its digits (the calculation repeated if required), is divisible by 9; andthe result of nine times the last digit subtracted from the number formed by the rest (the calculation repeated if required) is divisible by 13.
The number is 5.
Yes, and the result is 60.5 (any rational number is divisible by 2) but I suspect the questioner might be thinking of "divisible by 2 with no remainder". On that path you start out by finding 60, with remainder 1. Sometimes the question is put as "is it Exactly divisible by 2?". Again, technically any rational number is "exactly" divisible by 2, but the word "exactly" has commonly come to imply "without remainder". So be careful.
When one number is subtracted from another number, the result is known as the difference.