Forty
The number of different ways you can arrange the letters MNOPQ is the number of permutations of 5 things taken 5 at a time. This is 5 factorial, or 120.
There are 5 letters: a c e f and h.If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:5*5*5*5 = 54 = 625.
FOURFour, or Cinco (5) in Spanish.
The letters A B O U T can be arranged 120 different ways. This is the number of permutations of 5 things taken 5 at a time, or 5 factorial.
first -- 5 letters second -- 6 letters third -- 5 letters fourth -- 6 letters fifth -- 5 letters sixth -- 5 letters seventh -- 7 letters eighth -- 6 letters So the nest number would be 5, because there are 5 letters in ninth.
Five.
Forty
The number of different ways you can arrange the letters MNOPQ is the number of permutations of 5 things taken 5 at a time. This is 5 factorial, or 120.
The answer is number 5 F, I, V, E= 4 letters But, still has 5 when the 3 letters-"F", "I", "E" are removed because "V" stands for "5" as in the Roman numbers.
three
eight
Yes, glove has 5 letters.
i believe that the average letters for a first name is 5-9 letters
3
Since in the word "party" no letters are repeated, the letters can be arranged in 5! ways, or 120.
The number of different ways the letters of a word can be arranged, when all the letters are different, is the same as the number of permutations of those letters. In this case, the answer is 5!, or 120.