Please note that there are infinitely many solutions. The slopes of two perpendicular lines have a product of minus 1. The line is in slope-intercept form, so it is easy to read off the slope: -5. The line perpendicular to it must have a slope of -1 / -5, or 1/5. In other words, the equation of the perpendicular line is y = (1/5)x + c; you can replace c with any number you want.
Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3
-1 (negative 1)
negative 1
Yes and it will be a straight line intercepting y at -1 and parallel to the x axis
* / *: :* : * < ::::::::::: *:::::::::> : * : : / the stars are the line, it crosses the y-axis at 3 and the slope is negative 2
Negative association.
That's the equation of a straight line. Unless the line is horizontal (for m = 0), the y-coordinate of the line will always be positive for part of the line, and negative for another part of the line.
x = negative 1 is a vertical straight line parallel to the y axis at x = -1 ; its slope is infinite
Find an equati find an equation for the line perpendicular to the line 8x - 8 y equals negative 2 having the same Y intercept as -6x + 2 y equals negative 8
The slope is negative 2/3.
the line would look like a perfectly diagonal line. the line would be 45 degrees.
Two lines have slopes that are negative reciprocals if the product of their slopes equals -1. For example, if one line has a slope of 2, the negative reciprocal would be -1/2. This means that if one line rises 2 units for every 1 unit it runs, the other line falls 1 unit for every 2 units it runs, creating perpendicular lines.