16 and 31
A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.
58
59
29
solve it with a calculater
57
Since the remainder is 0 when the numbers are divided by 3, then that number is a multiples of 3. For example, 45/3 = 15 remainder 0 45/4= 11 remainder 1 45/7 = 6 remainder 3
3 divided by 2 has a remainder of 1. Which is 1 less than 2.
No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
103
4
The LCM of 2, 3, 4 and 5 is 60. Since you need a remainder of 1 just add 1. So the answer is 61. Or any number that is 1 more than a multiple of 60.