If a number is not divisible by 3 then it is not divisible by 9.

Yes, any number divisible by 9 is also divisible by 3.

Yes, every number that's divisible by 9 is divisible by 3

To check for divisibility by 9 sum the digits of the number and if this sum is divisible by 9 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 9 so 32643 is divisible by 9. As 9 = 3 × 3, any number divisible by 9 is also divisible by 3, thus as 32643 is divisible by 9 it is also divisible by 3. However, for completeness: to check for divisibility by 3 sum the digits of the number and if this sum is divisible by 3 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 3 so 32643 is divisible by 3.

9 is divisible by 1, 3 and 9.

There are many numbers between 500 and 1000 divisible by 3 and 9. Any number divisible by 9 is divisible by 3. How about 900?

999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.

Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.

3 and 9. 93 has a digit sum of 12, initially, which is divisible by 3, but not by 9. So 93 is divisible by 3, but not by 9. 99 has a digit sum of 18, initially, which is divisible by 3 and 9. So 99 is divisible by both 3 and 9.

The smallest number divisible by 3 6 and 9 is 18.

Except for zero, any number can divide into any other number. If the answer is a whole number, the larger number is said to be divisible by the smaller. 9 divided by 4 = 2.25 9 is not divisible by 4. 9 divided by 3 = 3 9 is divisible by 3.

No, 9 is divisible by 3 and 9, but not six 3 x 9 = 27, also not divisible by 6

Because 9 is divisible by 3, this is like the rule where if a number is divisible by 2 and 3 it is also divisible by 6.

NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)

Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 6 + 8 + 4 = 18 which is divisible by 3, so 684 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 684 is even so 684 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 684 is divisible by both 2 & 3 so 684 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 6 + 8 + 4 = 18 which is divisible by 9, so 684 is divisible by 9Thus 684 is divisible by all 3, 6 & 9.

9 ============================== Another contributor added more answers: Multiply 9 by any whole number. The answer is divisible by 3 and 9. There are an infinite number if them.

9

36360 is a 5 digit number that is divisible by both 3 and 9.

Because 9 is a multiple of 3.

No, 9 is not a prime number. In fact it is a composite number because it's divisible by 3.

If a number is even, it's divisible by two. If the digits of a number add up to a multiple of 3, it's a multiple of 3. For example, 342 is divisible by 3 because 3 + 4 + 2 = 9 and 9 is divisible by 3.

A prime number is not divisible by any numbers except 1 and itself. A composite number is divisible by other numbers. 9 is divisible by 3, so it is a composite number.

No. To check divisibility by nine, sum the digits. If they add up to 9 (or a multiple of 9) then the number is divisible by 9. This trick works for 9 divisibility and 3 divisibility. In this problem: 3 + 0 + 9 + 1 = 13, which is not divisible by 9. Suppose the number was 3591: 3+5+9+1=18, which is divisible by 9 (you can check 1+8=9). You can keep summing the digits of the new numbers till you get to a number which is either 9 or some other number. (If it's 3 or 6, then the number is divisible by 3)

Numbers divisible by 9 have the sum of their digits equal to 9 or a multiple of 9. A number divisible by 2 is an even number. If a 3 digit number is 42n then n can only be 3 if the number is divisible by 9 and 423 is not within the specified range. If a 3 digit number is 43n then n must be 2 for it to be divisible by 9.. The number is thus 432 and this is even and so divisible by 2. If the 3 digit number is 44n then n must be 1 and 441 is odd and not divisible by 2. The only valid solution is 432.

Yes. If the sum of a number's digits add up to 3 (or a multiple of 3) then the number is divisible by 3. 5 + 3 + 1 = 9 : as 9 is a multiple of 3 then 531 is divisible by 3 (177 x 3 = 531). NOTE : A similar process applies to identify if a number is divisible by 9. If the sum of the number's digits add up to 9 (or a multiple of 9) then the number is divisible by 9. 5 + 3 + 1 = 9 : 531 = 59 x 9.

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