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999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer.
Some shortcuts for divisibility:
0 is divisible by any number.
If the last digit of a number is divisible by 2, the number itself is divisible by 2.
If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3.
If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4.
If the last digit of a number is divisible by 5, the number itself is divisible by 5.
If a number is divisible by both 2 and 3, it is divisible by 6.
If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8.
If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9.
990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9.
18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.
What else can I help you with?
4-digit number divisible by 5 and 7?
To find a 4-digit number that is divisible by both 5 and 7, we need to find the least common multiple of 5 and 7, which is 35. The smallest 4-digit number divisible by 35 is 1005 (35 x 29 = 1005). The largest 4-digit number divisible by 35 is 9945 (35 x 284 = 9945). Therefore, the 4-digit numbers divisible by both 5 and 7 range from 1005 to 9945.
What is a 3 digit number that is divisible by both 3 and 5?
If it's to be divisible by 5, it must end in 5 or 0. And if it's to be divisible by 3, adding the digits together must result in a multiple of 3.The smallest such number is 105; the largest is 990.Since 3 x 5 = 15, all three-digit multiples of 15 would qualify. Note that 105 = 15 x 7, and 990 = 15 x 66.
Three digit number that is divisible by 4 and 9?
To be divisible by both 4 and 9 a number must be a multiple of the Least Common Factor of 4 and 9. The LCM is 36. The first 3 digit number in each hundred that is a multiple of 36 are as follows :- 108, 216, 324, 432, 504, 612, 720, 828 and 900.
Which digits should come in place of and if the no 62684 is divisible by both 8 and 5?
For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.
What is the divisibility rule for 15?
The number is divisible by both 3 and 5. A number is divisible by 3 if the sum of the digits are and by 5 if the last digit is 0 or 5. Ex: 863,145 Non Ex: 93,460
What is the largest 5-digit number that is divisible by both 24 and 50?
99,600 is the largest 5-digit number that meets both requirements.
What is the largest 5-digit number is divisible by both 2 and 3?
99,996
What is the largest three digit number divisible by both 3 and 10?
990.
What is the largest 5 digit number that is both divisible by 6 and 9?
99990
What is a three digit number divisible by 2 and 5?
A three-digit number divisible by both 2 and 5 must end with a 0, as this is the only digit that satisfies both conditions. The smallest three-digit number is 100, and the largest is 999. Therefore, any three-digit number that ends in 0, such as 100, 110, or 990, is divisible by both 2 and 5.
What is a three digit number that is divisible by three and four?
A three-digit number that is divisible by both three and four must also be divisible by their least common multiple, which is twelve. The smallest three-digit number divisible by twelve is 108, and the largest is 996. Therefore, any three-digit number that is a multiple of twelve, such as 120, 144, or 480, will meet the criteria of being divisible by both three and four.
What is the largest four digit number divisible by both 2 and 5?
The largest such number is 9990. 9990/2 = 4995, and 9990/5 = 1998.
What is the least three-digit number that is divisible by both 5 and 9?
The least three-digit number that is divisible by both 5 and 9 is 135.
What is the greatest four-digit number which is divisible by both 25 and 40?
9800 The LCM of 25 & 40 is 200, so need the largest multiple of 200 less than 10000. 10000 ÷ 200 = 50 so 49 x 200 = 9800 is the largest 4 digit number divisible by both 25 and 40.
What is the largest 5-digit number that is a multiple of both 4 and 9?
Oh, dude, you're hitting me with the math questions now? Alright, let me think for a sec... So, the largest 5-digit number is 99999, but that's not divisible by 4. The next largest one that works is 99996, which is divisible by both 4 and 9. So, there you go, 99996 is your winner. Math can be fun, right?
What 7 digit number is divisible by 5 and 9?
There are at least 2. One is 2657205 the other is 3515625.You're right!There are 200,000 of them.The smallest one is 1,000,035 .The largest one is 9,999,990.You're welcome.Here are some more:4999995999999010555202944485etc.Any 7 digit number divisible by 45 works.
What is a 5-digit number divisible by both 3 and 9?
27000
