Best Answer

999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer.

Some shortcuts for divisibility:

0 is divisible by any number.

If the last digit of a number is divisible by 2, the number itself is divisible by 2.

If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3.

If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4.

If the last digit of a number is divisible by 5, the number itself is divisible by 5.

If a number is divisible by both 2 and 3, it is divisible by 6.

If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8.

If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9.

990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9.

18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.

Study guides

☆☆

Q: What largest 3 - digit number divisible by both 6 and 9?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

144 is divisible by 2, 3, 4, 6, 9 and not divisible by 5 or 10.Divisible by 2The whole number is divisible by 2 if the number is even which is shown by the last digit being divisible by 2. The last digit of 144 is 4 and 4 is divisible by 2, thus 144 is divisible by 2.Divisible by 3The number is divisible by 3 if the sum of its digits is also divisible by 3. Sum of the digits of 144 is 1+4+4 = 9 which is divisible by 3, thus 144 is divisible by 3Divisible by 4The number is divisible by 4 is the last two digits is also divisible by 4. Last two digits of 144 are 44 which are divisible by 4, thus 144 is divisible by 4An alternative test: If the last digit plus twice the preceding digit is divisible by 4 then the whole number is divisible by 4.For 144, last digit + twice preceding digit is 4+2x4 = 12 which is divisible by 4, so 144 is divisible by 4Divisible by 5If the last digit is 0 or 5 then the number is divisible by 5 Last digit of 144 is 4 which is neither 0 nor 5, thus 144 is not divisible by 5Divisible by 6To be divisible by 6, the number must be divisible by both of 2 and 3. 144 is divisible by both 2 and 3 (see above), thus 144 is divisible by 6Divisible by 9If the sum of the digits of the number is divisible by 9, then the original number is divisible by 9. For 144, 1+4+4 = 9 which is divisible by 9, thus 144 is divisible by 9Divisible by 10To be divisible by 10, the last digit must be 0. The last digit of 144 is 4 which is not 0, thus 144 is not divisible by 10

The number is divisible by both 3 and 5. A number is divisible by 3 if the sum of the digits are and by 5 if the last digit is 0 or 5. Ex: 863,145 Non Ex: 93,460

For a number to be divisible by both 8 and 5 then : 1) the final digit must be zero (as a multiple of 5 ending in 5 is not divisible by 8) 2) As 1000 is divisible by 8 then only the last 3 digits of the number need to be checked to confirm if it is divisible by 8. 680 ÷ 8 = 85. Therefore the number has to be changed to 62680 to be divisible by both 8 and 5. Therefore, replace the digit 4 in 62684 with 0.

The smallest one is 1,008. The largest one is 9,990. In all, there are 500 of them, all of them even numbers divisible by 9. (To find them all, multiply 18 by all integers from 56 to 555.)

Quickly check to see whether it's divisible by both 2 and 3. Here's how to do that easily: -- The number is divisible by 2 if it's an even number . . . the last digit is 2, 4, 6, 8, or 0. -- The number is divisible by 3 if the sum of its digits is divisible by 3.

Related questions

99,600 is the largest 5-digit number that meets both requirements.

99,996

990.

99990

The largest such number is 9990. 9990/2 = 4995, and 9990/5 = 1998.

The least three-digit number that is divisible by both 5 and 9 is 135.

9800 The LCM of 25 & 40 is 200, so need the largest multiple of 200 less than 10000. 10000 ÷ 200 = 50 so 49 x 200 = 9800 is the largest 4 digit number divisible by both 25 and 40.

54

54.

99999

How about: 108

27000