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Q: What number when divided by 5 has a remainder of 3?

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The number is 119. 119/2= 64 R1, 119/3 = 39 R2, 119/4 = 29 R 3, and finally 119/5 = 23 R4. Hope this helps!

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solve it with a calculater

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Dividing by 3 and then by 5 is equivalent to to dividing by 15; therefore, the remainder will be the same.

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62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.

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The LCM of 2, 3, 4 and 5 is 60. Since you need a remainder of 1 just add 1. So the answer is 61. Or any number that is 1 more than a multiple of 60.

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179 works until divided by 7 the remainder is 6. 2519 works till 10....

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No, the remainder can only be 1,2, or 3

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The answer is 8.

A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.