100 is divisible by 5. The next is 105, the next is 110, and so on forever.
There are 14 numbers between 1 & 100 that are divisible by 7.
Any of its multiples up to 100
The numbers divisible by nine up to a 100 are 9,18,27,36,45,54,63,72,81,90,and,99
25
Any number ending in a 5 or 0 !
Just count up all the even numbers which will all be divisible by 2
100 / 8 = 12.5. Rounding this up gives you 13, therefore 13 x 8 is the first multiple of 8 (i.e., number divisible by 8) in the desired range. After that, simply add 8 at a time to get additional multiples.
42, 48, 54, and 60 is. -- If it's 'even' then it must also be divisible by 2 . -- If it's divisible by 3 and also by 2, then it must be divisible by 6 . -- The multiples of 6 between 40 and 60 are 42, 48, 54, and 60 .
The natural numbers between 9 and 100 are 10, 11, 12, ..., up to 99. This includes all whole numbers starting from 10 up to 99. In total, there are 90 natural numbers in this range.
The first one is (1 x 3) = 3The second one is (2 x 3) = 6The fifth one is (5 x 3) = 15....The thirty-third one is (33 x 3) = 99.and that's as far as you can go. There are 33 of them.
Numbers up to 200 divisible by both 2 and 3 = numbers to 200 divisible by 2*3 = 6 which is int(200/6) = int(33.33) = 33
Counting up from 1, there is a number divisible by 3 every 3 numbers. Thus to find out how many numbers are divisible by 3, we just have to divide the number we're counting to by 3. In this case, the top number is 50, so do: 50/3 = 16 with two remainder. Because the numbers divisible by 3 come last in every set of 3 numbers, we can discard the remainder. Therefore there are 16 numbers between 1 and 50 that are divisible by 3.