100 is divisible by 5. The next is 105, the next is 110, and so on forever.
There are 14 numbers between 1 & 100 that are divisible by 7.
Any of its multiples up to 100
The numbers divisible by nine up to a 100 are 9,18,27,36,45,54,63,72,81,90,and,99
25
Any number ending in a 5 or 0 !
Just count up all the even numbers which will all be divisible by 2
100 / 8 = 12.5. Rounding this up gives you 13, therefore 13 x 8 is the first multiple of 8 (i.e., number divisible by 8) in the desired range. After that, simply add 8 at a time to get additional multiples.
Numbers up to 200 divisible by both 2 and 3 = numbers to 200 divisible by 2*3 = 6 which is int(200/6) = int(33.33) = 33
42, 48, 54, and 60 is. -- If it's 'even' then it must also be divisible by 2 . -- If it's divisible by 3 and also by 2, then it must be divisible by 6 . -- The multiples of 6 between 40 and 60 are 42, 48, 54, and 60 .
Numbers that are divisible by three from 1 through 100 are multiples of three. To find these numbers, you can start with 3 and continue adding 3 until you reach 99, as 100 is not divisible by 3. So, the numbers divisible by three from 1 through 100 are 3, 6, 9, 12, 15, and so on, up to 99.
Counting up from 1, there is a number divisible by 3 every 3 numbers. Thus to find out how many numbers are divisible by 3, we just have to divide the number we're counting to by 3. In this case, the top number is 50, so do: 50/3 = 16 with two remainder. Because the numbers divisible by 3 come last in every set of 3 numbers, we can discard the remainder. Therefore there are 16 numbers between 1 and 50 that are divisible by 3.
A number is divisible by 9 if all the digits add up to 9 or are a factor of. IF the digits add up to 9 (or a factor of 9), they will automatically be a factor of 3.Yes. Test a couple numbers divisible by 9--27, 81--and they are all divisible by 3.