Any multiple of 21
5, 7, a bunch of numbers that are odd are not divisible by 3. numbers that are divisible by three can have all their numbers added together and come out with a number that is divisible by 3.
Oh, what a lovely question! Let's see, we can find the numbers divisible by 3 first, which are 33 numbers, and the numbers divisible by 7, which are 14 numbers. But wait, some numbers are divisible by both 3 and 7, so we must be careful not to count them twice. In the end, there are 47 numbers between 1 and 100 that are divisible by 3 or 7. Happy counting!
1, 3, 7, 21
No, the number 1155 is divisible by four prime numbers (3, 5, 7, 11).
Numbers that are divisible by 2, 3, and 7 must be divisible by the least common multiple of these three numbers, which is 42. Therefore, any number that is a multiple of 42 will be divisible by 2, 3, and 7 simultaneously. Examples of such numbers include 42, 84, 126, 168, and so on.
They are members of the infinite set of numbers of the form 21*k where k is an integer.
6 is the only number from 2-7
Yes. It equals 45. A quick rule for numbers to see if they are divisible by 3 is to add all the numbers, for example: 207 = 2 + 0 + 7 = 9 Is 9 divisible by 3...Yes! It helps reduce the large numbers, for an easier answer. The number 8649... 8 + 6 + 4 + 9 = 27 and 27 is divisible by 3, so 8649 is also divisible by 3. BUT...137: 1 + 3 + 7 = 11 11 is not divisible by 3...so, 137 is not divisible by 3.
19 of them.
That's an infinite list.
1,3,5,7,9 Odd numbers are the ones that if you repeatedly subtract 2 from, you will end with 1. Odd numbers always end in 1, 3, 5,7, and 9. Examples: 23, 37, 51, 69, 75, 87, 99
all numbers are divisible by 7.