Any multiple of 21
5, 7, a bunch of numbers that are odd are not divisible by 3. numbers that are divisible by three can have all their numbers added together and come out with a number that is divisible by 3.
Oh, what a lovely question! Let's see, we can find the numbers divisible by 3 first, which are 33 numbers, and the numbers divisible by 7, which are 14 numbers. But wait, some numbers are divisible by both 3 and 7, so we must be careful not to count them twice. In the end, there are 47 numbers between 1 and 100 that are divisible by 3 or 7. Happy counting!
1, 3, 7, 21
No, the number 1155 is divisible by four prime numbers (3, 5, 7, 11).
Numbers that are divisible by 2, 3, and 7 must be divisible by the least common multiple of these three numbers, which is 42. Therefore, any number that is a multiple of 42 will be divisible by 2, 3, and 7 simultaneously. Examples of such numbers include 42, 84, 126, 168, and so on.
They are members of the infinite set of numbers of the form 21*k where k is an integer.
6 is the only number from 2-7
Yes. It equals 45. A quick rule for numbers to see if they are divisible by 3 is to add all the numbers, for example: 207 = 2 + 0 + 7 = 9 Is 9 divisible by 3...Yes! It helps reduce the large numbers, for an easier answer. The number 8649... 8 + 6 + 4 + 9 = 27 and 27 is divisible by 3, so 8649 is also divisible by 3. BUT...137: 1 + 3 + 7 = 11 11 is not divisible by 3...so, 137 is not divisible by 3.
19 of them.
That's an infinite list.
all numbers are divisible by 7.
1,3,5,7,9 Odd numbers are the ones that if you repeatedly subtract 2 from, you will end with 1. Odd numbers always end in 1, 3, 5,7, and 9. Examples: 23, 37, 51, 69, 75, 87, 99