The common factors are: 1, 2
To find out how many times 14 goes into 120, you can divide 120 by 14. The quotient is the number of times 14 goes into 120. When you divide 120 by 14, you get 8 with a remainder of 8. So, 14 goes into 120 8 times with a remainder of 8.
Not evenly because there will be a remainder of 8
The numbers are: 20 and -6
Simultaneous equations A-B=14 (1) AB=120 (2) transposing(1) A=14+B substituting into(2) B(14+B)=120 B^2+14B =120 B^2+14B-120=0 solve quadratic (B+20)(B-6)=0 B=-20,6 one of the whole numbers is 6 and the other is 6+14=20
The numbers are 6 and -20
1, 2, 3 and 6 will go into both numbers
Oh, dude, you're hitting me with some math vibes! So, the two numbers we're looking for are -12 and -10. They multiply to 120 and add up to -14. It's like a math puzzle, but with numbers instead of jigsaw pieces.
14% of 120= 14% * 120= 0.14 * 120= 16.8
The numbers are: 1 and 2
The HCF of both numbers is 14
9 and 5
15