5y + 7 = 25y = -5y = -1
- X + 5Y - 4X + 7 gather terms - X - 4X ( same as - X + (- 4X ) 5Y 7 = - 5X + 5Y + 7 ----------------
8+y = 7+5y y-5y = 7-8 -4y = -1 y = 1/4
5y+14+y = 3y-7 5y+y-3y = -7-14 3y = -21 y = -7
3x/7 + 5y/14x = 3x*2x/(7*2x) + 5y/14x = (6x2 + 5y)/14x
7 + 8y - 3y + 2 =7 + 2 + 8y - 3y = 9 + 8y - 3y = 9 + 5y
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
It is y = -7
7
5y+8 = 7y-6 5y-7y = -6-8 -2y = -14 y = 7
2y - 7 + 5y = 0 Collecting like terms together, 7y - 7 = 0 or 7y = 7 So that y = 1
Is this a system of equations? 2X + 5Y = 4 X + 5Y = 7 solve for X using bottom equation X = 5Y - 7 insert into top equation 2(5Y - 7) + 5Y = 4 distribute 10Y - 14 + 5Y = 4 solve for Y 15Y = 18 Y = 18/15 = 6/5 use bottom equation to find X X +5(6/5) = 7 X = 1 check with bottom equation 1 + 5(6/5) = 7 7 = 7 not true for top equation ( sorry, I forgot what happens then-resubmit question )