Most 3D shapes, such as a cube, cuboid etc. have more than one face (with the possible exception of a sphere).
Oh, dude, that's an easy one. A shape like a cube has more faces than vertices. Like, think about it, a cube has 6 faces but only 8 vertices. So, yeah, the faces totally outnumber the vertices in that situation.
There are several but there is one that comes to mind that has 20 congruent triangular faces called an icosahedron.
There are numerous answers to this, but if you were looking for just one the answer could be a dodecahedron.
A shape in fewer than 3 dimensions.A shape with one or more curved faces or edges.
That's impossible. A shape has three or more sides/faces. There is NO shape that has one or two sides/faces
There are infinitely many polyhedra with one or more triangular faces.
Only one; a triangle is a 2D shape, not a 3D shape. Usually only 3D (or more) shapes are considered to have 'faces'.
A cube has 6 faces. That leaves us with two faces. Any 2-dimensional shape will have 2 faces, one on the visible side and the other on the reverse side. I don't think I've convinced myself.
yes
a hexagon * * * * * or any one of infinitely many polygons with 5 or more sides; any one of an infinite number of polyhedra with more than 4 faces, as well as other shapes that do not fit into these classifications: for example, a closed plane shape with five curved sides which meet pairwise.
There is no such shape - unless there are other faces. If there is one rectangular face then you require at least four other faces - one on each edge of the rectangle - making a minimum of 5 faces.
A 2D shape does have one face.