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Q: What size ground wire needed for 75 amps at 208 volts?

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14 gauge copper

10 AWG in copper.

To calculate the wire size, a system voltage is needed.

Depending on size of Fridge. But AVERAGE is 12 volts for fridge, circuit necessity 15 amps 15 amps X 120 Volts=1800 watts minimum...I'm LEARNING myself

3/0 or250 aluminum

The formula you are looking for is Watts = Amps x Volts. Amps = Watts/Volts. This comes to 4 amps load. Minimum size fuse would be 5 amps.

14 AWG is fine for this application.

A # 14 copper conductor will be fine to carry 8 amps at 120 volts. This size conductor is rated at 15 amps.

It's not the volts that you consider it is the amperage. 30 amps = #10 40 amps = # 8 55 amps = # 6 100 amps = # 3 200 amps = # 3/0

The V stands for volts and A is amps. If for example you have a 12kVA device and are running off a voltage of 120 volts then Amps = 12000/120 = 100. You then use the calculated amps in a wire size table to get the correct size.

Wire is sized by the amperage that it will carry. 5 kW is 5000 watts. The equation to find watts is W = Amps x Volts. The equation to find amps is Amps = Watts/Volts. As you can see a voltage is needed to calculate the amperage. Once the amperage is stated, the wire size can be given for that particular amperage.

Wire size is based on amperage of the load. I = W/E. Amps = Watts/Volts. As you can see with out a voltage stated an answer can not be given.