Loaded question, what is the voltage, run length, aluminum or copper feeders, expected constant load? Definitely bigger than 4/0
We recommend using a #6 copper wire for the connection between the breaker box and the earth ground rod. This size wire is commonly used for grounding purposes and is sufficient for carrying the electrical current safely to the ground rod. Be sure to consult with a qualified electrician to ensure the proper materials and installation for your specific situation.
There are two distinct questions here. To determine the wire size to carry 15000 volts the circuits load amperage must be stated. The wire size for a 550 amp service is, an 800 MCM copper conductor with an insulation factor of 90 degrees C. This conductor is rated at 555 amps. Parallel 250 MCM will give you a total capacity of 580 amps. A triple run of 2/0 will give you a total capacity of 585 amps.
A duralast gold from walmart,640 cold cranking amps(800 cranking amps)
A 400 watt heater can safely be used on a 15 amp circuit. The size breaker needed for a circuit is determined by the size of the wiring in that circuit. AWG #14 wire requires a 15 amp breaker. AWG # 12 wire requires a 20 amp breaker.
530 amps in average conditions, more in cold weather. <<>> The closest conversion will be; 405 mm2 is equal to 800 MCM AWG. A 800 MCM aluminium conductor with an insulation factor of 90 degrees C is rated at 445 amps.
There is no better, but 800 is more cranking power that 650.
For an 800 amp service, typically a 3/0 or 4/0 copper conductor or 250kcmil aluminum conductor would be appropriate for the grounding wire. However, it is recommended to consult with a qualified electrician or the local electrical code for specific requirements based on the installation conditions.
A 500 MCM copper conductor will limit the voltage drop to 3% or less when supplying 50 amps for 800 feet on a 120 volt system. 500 MCM wire diameter is 1/2 inch. As you can see there will be trouble getting that size wire into a 50 amp breakers lug. On installations like this to offset the voltage drop at such a low voltage, a transformer should be used at both ends. The first transformer to raise the voltage and the second transformer to lower it at the 800 foot end. If you use two 480 volt transformers a #1 wire can be used between them. A #1 copper conductor will limit the voltage drop to 3% or less when supplying 50 amps for 800 feet on a 480 volt system. By increasing the voltage you can see that a smaller wire size can be used. On an installation of this nature, a primary line should be brought to the RV site and a service distribution panel established at that point and any RV vehicles can then be fed from that service.
0.8 amps is equivalent to 800 milliamps.
A 3/0 copper conductor would allow you up to 100 feet at 800 Amps with only 5 percent voltage drop, assuming 240-volt service. If it were a 3-phase 480-volt service, you could go more than 23 feet with only a 5 percent drop. <<>> The size of conductors for an 800 amp service could be sized in several ways. Using a single conductor is out of the question as the size will be impossible to bend or handle. A 2000MCM wire only has a rating of 775 amps. Most high amperage services will use parallel runs to add up to the required amperage. A parallel run of 600 MCM will give you a total of 910 amps. A triple parallel run of 300 MCM will give you a total of 885 amps. A quad parallel run of 3/0 will give you an amperage of 840 amps. The key here is to find the most economical way of installing the service. Take into account the availability of triple barrel or four barrel lugs, wire costs for the larger sizes and the labour to man handle the larger sizes into the main switch. These size services that I have installed, the customer opted for the four barrel lugs with 3/0 wire. The 3/0 wire is a readily available item even though the lugs may have to be a special order.
A voltage needs to be stated. Assuming the question is from North America 120 volts will be used. Assuming that the 800 watts is for each outlet that is a total of 2400 watts. The electrical code states that a conductor in continuous use can only be loaded to 80% capacity. I = W/E = 2400/120 = 20 amps. A #14 conductor is rated at 15 amps x 80% = 12 amps. A #10 conductor is rated at 30 amps x 80% = 24 amps. So to answer the question, no a 14 gauge wire and a 15 amp breaker will not handle 3 outlets using 800 watts.
T= timedelay 800= ? L=? 250V= volts