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What the integers of three consecutive integers are such that three times the largest exceeds the sum of two smaller integers by 47?
Wiki User
∙ 11y ago
We have three integers, and we know they are all sequential integers, so we can refer to them as:
x, x + 1, x + 2
We are also told:
3(x + 2) = x + (x + 1) + 47
Now we can use that relationship to solve for x:
3x + 2 = 2x + 48
x = 46
So our numbers are 46, 47 and 48
Wiki User
∙ 11y ago
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