Using the quadratic formula where a=2, b=1, c=-1
x = [-b +- SQRT (b2-4ac)]/2a
Plugging in the coefficients a,b,c we solve for x and get:
x = 1/2 and x = -1
It can't be solved because its discriminant is less than zero
Without an equality sign the given expression can't be considered to be an equation but if it equals 0 then using the quadratic equation formula will give its solutions.
Using the quadratic equation formula: x = -5-/+ the square root of 7
0x2 + 1x - 7 = 0
The solution: x = 6/7 and x = -1
There is no integer solution. Quadratic formula gives x = -17.66 or 5.66
The first step is to show an example of the quadratic equation in question because the formula given is only the general form of a quadratic equation.
It can't be solved because the discriminant of the given quadratic equation is less than zero meaning it has no real roots.
It will have two solutions because its a quadratic equation: x = -8.472135955 or x = 0.472135955
Quadratic - the degree is two.
It is a quadratic equation that has 2 solutions
It is a quadratic equation that can be solved by using the quadratic equation formula whereas x = -9.321825 or x = 0.321825 both given to 6 decimal places