45 and 90
The LCM is 90
You need at least two numbers to find an LCM.
You need at least two numbers to find an LCM. If that's 3 and 8, the LCM is 24.
Designate the smaller number as s. From the statement of the problem, s + s +12 = 90; or 2s = 90 -12 = 78; s = 39
You need at least two numbers to find an LCM.
This is only possible if one of the digits is equal to zero. There are 90 3-digit numbers with a zero in the 10's place, and 90 3-digit numbers with a zero in the 1's place - and 9 numbers that have both a zero in the 10's place and a zero in the 1's place; these would be counted double if you just add the first two. So, you get: 90 + 90 - 9 such numbers.
No.
Start by factoring both numbers into primes: 210 = 2*3*5*7 450= 2*3*3*5*5 What's the shortest list that includes all the factors of both numbers? One 2, two 3's, two 5's, one 7 That's the recipe for lcm in this problem. lcm = 2*3*3*5*5*7 = 3150
There is only one: 97.
Find the LCM by finding prime factorization of both numbers:100 = 2 * 2 * 5 * 5130 = 2 * 5 * 13Then, count each pair of prime numbers. The two factorizations have two pairs of prime numbers: one pair of 2's and one pair of 5's (pairs are bolded, above):Paired primes: 2, 5Next, count the remaining primes and multiply them with the paired primes.Paired primes: 2, 5Unpaired primes: 2, 5, 13The LCM of 100 and 130 is2 * 2 * 5 * 5 * 13 = 1300
The numbers in the 90s are all composite, apart from 97, which is prime.
Multiples of 10 include any number ending in zero. You need at least two numbers to find an LCM.