the LCM of (a) and (b) is (ab) divided by (gcf of a and b) In this case, (a)=9 (45) = (9x)/(1) 45 = 9x 5= x ◄
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Each of 45's factors (1, 3, 5, 9, 15, 45) can be divided into 45 and result in a whole number.
the least common multiple is the lowest number that 5 and 16 (or any other numbers) go into that equal. for example, the lowest common multiple (LCM) of 5, and 10, is 10. because that is the lowest number that 5 and 10 will go into. so the lowest common multiple of 5 and 16 = 80.there are two ways to solve, one by counting by the number: for example5: 5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,8016: 16,32,48,64,80the lowest number that is the same in both of these is 80.Second way to solve:find the prime factors of both 5 and 16: For example16^8 2^4 2^2 25:516:2x2x2x2now count the most amount of prime numbers in both 5 and 16.so there are 5's and 2's. So there is only one 5, and four 2's. now multiply 5 times four 2's.so it would look like 5x2x2x2x2= (LCM)5x2=1010x2=2020x2=4040x2=80See, there are four 2's and one 5.Hope this helped!It is: 80
1, 3, 5, 9, 15, 451 x 45, 3 x 15, 5 x 9, 9 x 5, 15 x 3, 45 x 1
It is: 70
45 and 90
The LCM of 12, 15, and 45 is 180. The 15 can be ignored since it is already a factor of 45, next you break down the remaining numbers into their prime factors. 12= 2x2x3 45=3x3x5 You can eliminate 1 of the 3's since it is already a common actor between them So then 2x2x3x3x5=180
Their product.
10 S 45 W is the State of Piauí, Piauí, Brazil.
1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90
the LCM of (a) and (b) is (ab) divided by (gcf of a and b) In this case, (a)=9 (45) = (9x)/(1) 45 = 9x 5= x ◄
there are 5
55
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Order is not important, so this is a combination problem. There are 5 odd numbers from 1 to 10. n(E) = 5C2 = 5*4/2*1 = 10 n(S) = 10C2 = 10*9/2*1 = 45 P = n(E)/n(S) = 10/45 = 2/9
15