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Q: What two two-digit numbers are each equal to their right-most digit squared?

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25 and 36 are each equal to their rightmost digit squared. 25 = 5 X 5 36 = 6 X 6

300

The units digit of a whole number is always the rightmost digit.

Hint, but not your answer: You know your answer has to be between 11 and 99. Furthermore, it has to be a square. One, two, and three when squared are still single digit numbers. Four squared is 16, which is not squaring the ones digit. Keep going...

When you square a number, the final digit is the final digit of the 'one's' number squared. Since the only single digit numbers squared which ends in 6 are 4 and 6, the answer is either 4 or 6 (a calculator tells me it is 6) 0 squared is 0. All numbers ending in 0 when squared will end in 0. 1 squared is 1. All numbers ending in 1 when squared will also end in 1. 2 squared is 4. All numbers ending in 2 when squared will end in 4. 3 squared is 9. All numbers ending in 3 when squared will end in 9. 4 squared is 16. All numbers ending in 4 when squared will end in 6. 5 squared is 25. All numbers ending in 5 when squared will end in 5. 6 squared is 36. All numbers ending in 6 when squared will end in 6. 7 squared is 49. All numbers ending in 7 when squared will end in 9. 8 squared is 64. All numbers ending in 8 when squared will end in 4. 9 squared is 81. All numbers ending in 9 when squared will end in 1. So square numbers can only end with 0, 1, 4, 5, 6 or 9.

It is the integer that you get by dividing the three digit number by 10. Alternatively, the number of the multiples of ten is that you get when you truncate the rightmost number. for example assume a three digit number 517 Divide 517 by ten, you get 51.7 The integer number is 51 Alternatively, if you trnucate the rightmost number (7) you get 51 also then the answer the three digit number 517 has 51 multiples of 10.

4 Every digit between the leftmost non-zero digit and EITHER the right most non-zero digit OR the rightmost digit after a decimal.

N squared would be used to find the square root of a number or numbers. In order to find the number of three digit numbers such that the sum of the square results of any two digits are equal to the third digit the use of the formula (HOE)squared=Hsquared*10000+2HE*100+Esquared is needed.

int n; // the number you want to reverse int rev_n = 0; while (n > 0) { // shift rev_n digits left rev_n *= 10; // put rightmost digit of n onto right of rev_n rev_n += n % 10; // remove rightmost digit of n n /= 10; }

Any two digit nuber from 10-99 can be squared or cubed.

3 digit numbers are lessthan 4 digit numbers

10. Any number can be squared or cubed.

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