3 digit numbers are lessthan 4 digit numbers
A 3 or 4 digit number.
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
-3
24 = 4*3*2*1
To form 4-digit numbers using the digits 4, 7, 6, and 0, we must ensure that the first digit is not 0. The valid choices for the first digit are 4, 7, or 6, giving us 3 options. After choosing the first digit, we can arrange the remaining 3 digits in any order, resulting in (3! = 6) arrangements for each choice of the first digit. Thus, the total number of 4-digit numbers is (3 \times 6 = 18).
A 3 or 4 digit number.
The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2. 5
81 As there are no limits stated then you can have a number comprising a repeated single digit (such as 2222), two pairs of numbers (e.g. 2244) or three different numbers (such as 2462). The first digit can be one of any of the 3 numbers. The second digit can be one of any of the three numbers, as can the third digit and also the fourth. Then you can have 3 x 3 x 3 x 3 = 81 different 4-digit numbers using the three given numbers.
There are 4 options for the hundreds digit (3, 4, 5, or 6), and 4 options for the tens digit (including the possibility of repeating the hundreds digit). Similarly, there are 4 options for the units digit. Therefore, the total number of 3-digit numbers that can be formed using the digits 3, 4, 5, and 6 with repetition allowed is 4 x 4 x 4 = 64.
4C3 = (4!)/(4 -3)!3!] = (4 x 3!)/(1!3!) = 4 ways
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
-3
24 = 4*3*2*1
When the repetition is allowed: 4*4*4 = 64 numbers. Without repetition: 4*3*2 = 24 numbers.
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
The diference between the highest 4 digit number and the lowest 3 digit number is 9999 Highest 4 digit: 9999 Lowest 3 digit: 000
There are 3 values (1, 2, 3) for each of the 4 digits. Therefore, there are 3*3*3*3 or 81 four digit numbers that can be formed.