It will be 9 times as large. And that will be true for any plane shape, not just an equilateral triangle.
There is only one basic shape for an equilateral triangle. The area can only vary as the length of the sides vary.
The area is 1.2 (1.16463) m2
If the sides are different lengths it ain't equilateral...
In our example, the area of the equilateral triangle is 1/6 of the area of the regular hexagon
225(radical "3")/4
By definition, an equilateral triangle has all three sides of equal length! So it is impossible for it to have sides of length 10 inches and 7 inches!
27.713 square inches.
The area is: 15.6 (15.58846) square inches.
Area of Equilateral Triangle A= S2 * (Root 3)/4, where A= Area of the triangle S= Side of the triangle.
60 because there are 3 sides in a triangle and 60 x 3 =180, triangles are always equal to 180 * * * * * The above "answer" has nothing to do with the question! The area of an equilateral triangle with sides of s cm is s*sqrt(3)/4 square cm.
Given this area, the sides measure 52.92734 cm
There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.