Only one selected 68%
The answer would depend on the demographics of the population: a probability of 0.2 it too high unless the population is from a retirement area.
366 x 2 = 732 I don't think so. You might find that you would select 366 individuals with distinct birthdays. However, the next person would inevitably have the same birthday as one of those already selected. Therefore, the minimum number to select is 367.
The probability that a single person would like at least ONE flavour - is 9/10 * * * * * No. 350 liked only Vanilla 250 liked Vanialla and Chocolate 50 liked only Chocolate That makes 650 [the remaining 350 did not like either]. Therefore the probability that a randomly selected person likes at least one of the two tastes is 650/1000 or 65%
The probability is close to 0. You would need to know details of all the companies in the world that filed reports. Chances of finding one whose profits were exactly 63% are pretty slim!
The theoretical probability of getting an odd product would depend on the specific scenario. If we are talking about rolling a pair of fair dice, the probability would be 1/2 since half of the possible outcomes (3, 5, 15, etc.) would result in an odd product. However, if we are talking about multiplying two randomly selected numbers from a large set, the probability would depend on the distribution of the numbers in the set.
The probability of event e would be the number of girls, 8, divided by the total number of children, 13; or 8/13 or 0.615385.
There are five letters, and two of them are s's. The theoretical probability of choosing an s would be 2 out of 5.2/5 or 40%
Yes, probability can be expressed as a percent. It is common to express probabilities as a percentage, which is calculated by multiplying the probability by 100. For example, if the probability of an event is 0.25, it can also be expressed as 25%.
We will use Q and P to help solve this problem with Q representing the possibility that none of the randomly selected people are vaccinated and P representing the possibility that at least 1 randomly selected person is vaccinated. Because the sum of all probabilities must equal 1, your beginning equation will be P=1-Q. First you need to figure out how much of the population is NOT vaccinated so you would take 100%-54% to get 46%. With that 46%, you can conclude that any given person has the probability of 0.46 of not being vaccinated. To find the value for Q we will take (0.46)^5. Q=(0.46)^5=0.0206. To find P we go back to the original equation of P=1-Q. P=1-0.0206=0.9794. The probability that at least 1 person has been vaccinated is 0.9794.
In the context of the usage 1000%, it would be sure to happen. As far as probability is concerned, the probability of certain is 1 or 100%.
The Population of the data set. If there was a study of 5000 people, 50 were randomly selected as a sample, then "N" would be 5000.
your probability would be 13/13. you would have a 100 percent chance of getting a green marble