For the product of two integers the answer is 1/4 or 0.25
1 whole
To find the probability of getting an odd number at least once when a die is tossed thrice, we can use the complementary approach. The probability of not getting an odd number (i.e., getting an even number) in a single toss is ( \frac{3}{6} = \frac{1}{2} ). Therefore, the probability of getting an even number in all three tosses is ( \left(\frac{1}{2}\right)^3 = \frac{1}{8} ). Thus, the probability of getting an odd number at least once is ( 1 - \frac{1}{8} = \frac{7}{8} ).
It is 0.5
The answer depends on how many dice you roll and how often. If you roll four dice once, the probability of getting a double AND two odd numbers is 264/1296 = 11/54
If you have an equal amount of odd and even numbers in a determined sample space, the probability of choosing and odd number is 1/2 (.5).
The probability of rolling an odd number on a standard die is 3 in 6, or 1 in 2, or 0.5.
I'm assuming you multiply the numbers rolled. Thus the rules of even and odd numbers come into play. The only way to get an odd product is to roll two odd numbers. The probability desired is 1 minus the probability of rolling two odd numbers. The odds of rolling an odd number is 1/2. Since the rolls are independent events, the odds of rolling two odd numbers is (1/2)2 = 1/4 So the probability of getting an even product is: 1 - 1/4 = 3/4
The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.
The probability of getting an odd number when you roll one die is 1 in 2. In order to get an odd sum with two dice, one of them has to be odd and one of them has to be even. The probability of rolling an odd sum is still 1 in 2, since each die is unrelated in probability to the other.
1 whole
There are 3 odd numbers, 1, 3 and 5 so the probability of getting an odd number is 3 out of 6 or 1/2. This can also be written as .5 of course.
To find the probability of getting an odd number at least once when a die is tossed thrice, we can use the complementary approach. The probability of not getting an odd number (i.e., getting an even number) in a single toss is ( \frac{3}{6} = \frac{1}{2} ). Therefore, the probability of getting an even number in all three tosses is ( \left(\frac{1}{2}\right)^3 = \frac{1}{8} ). Thus, the probability of getting an odd number at least once is ( 1 - \frac{1}{8} = \frac{7}{8} ).
The probability of rolling an odd number of a standard die is 3 in 6, or 1 in 2, or 0.5.
It is 0.5
50%
There are three odd numbers in a die: 1, 3, 5. The probability of rolling an odd number in a fair die is: P(1 or 3 or 5) = 3/6 = 1/2
It is 0.5