There are five letters, and two of them are s's. The theoretical probability of choosing an s would be 2 out of 5.
2/5 or 40%
dictinct object or letters- It implies that each object or letters differs in some way from the every other object or letters in the set Ex. Banana=B,a,n distinct letters
If you are referring to sets of letters, then yes. But if you are referring to individual letters, they are called letters, not alphabets.
There are many ways to solve different maths codes. some may work with numbers turning into letters others may work with letters turning into different letters. some codes may have a letter 3 letters after it so say if the code was; ALD. 3 letters after A is D 3 letters after L is O and 3 letters after D is G so the word would spell "dog".
The number of different ways the letters of a word can be arranged, when all the letters are different, is the same as the number of permutations of those letters. In this case, the answer is 5!, or 120.
you need to use something called factorial. this is represent by an exclamation point and means that you multiply its successive numbers. lets say you have 4! this means 4 * 3 * 2 * 1 = 24 lets say you have 11! this means 11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 =39,916,800 so now lets take your word "constitution" and how many letters do you have. you have 12 letters. so to figure out how much arrangements you can do you need to do 12! this number is 479,001,600. this is combinatorics. it is used in making combinations and figuring them out. also it can be used in probability and password hacking and protection.
There are 5 letters in the set {a, b, c, d, e}, and 2 of these letters are vowels (a, e). Therefore, the probability of randomly choosing a vowel from this set is the number of favorable outcomes (2 vowels) divided by the total number of possible outcomes (5 letters), which equals 2/5 or 0.4.
Theoretical
Theoretical
Since the word "probability" contains only letters, then the probability of choosing a letter from the word "probability" is 1, i.e. it is certain to happen.
The probability for a single random choice, is 6/13.
Word 1) 'math' has one vowel letter among a total of 4 letters. The probability of randomly selecting the vowel letter 'a' is P(v) = 1/4. Word 2) 'jokes' has two vowel letters among a total of 5 letters. The probability of randomly selecting a vowel letter is P(v) = 2/5. The probability of randomly selecting a vowel letter from the first word and a vowel letter from the second word is: P(v1,v2) = 1/4 (2/5) = 2/20 = 1/10 = 0.10 = 10.0%
If the letters of computer are randomly arranged in all possible ways, the probability the word begins with a vowel in five out of 26, or 0.1923. You do not need to consider any other letters, or any permutations or combinations, because you only asked about the first letter.
3 out of 6
There are 11 letters in the word mathematics. 2 of those 11 are A's. Probability is therefore 2/11.
The sample space consists of the letters of the word "PROBABILITY" = {P,R,O,B,A,I,L,T,Y}
There are 10 letters in the word "aspiration" and 5 of them are vowels. The probability of a randomly-selected letter being a vowel are 5/10 = 1/2 = 0.50.
"Puzzle" has 6 letters, and 2 of them are vowels. So the odds of choosing a vowel are 2/6, which equals 1/3, which is one-third or 33.33%.