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Q: What would you add to the 13678 as the last digit to make them divisible by 4?

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To be divisible by 5, the last digit must be 0 or 5. The last digit of 305 is 5, so it is divisible by 5.

no

Any number whose last digit is 0 would be divisible by both these numbers. 1000, 1010, 1020...

Not evenly. You get 43.2 as the answer. To be divisible by 10, the last digit must be 0 The last digit of 432 is 2 which is not 0, so it is not divisible by 10.

All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 117 is a 7 which is NOT a 0, so 117 is NOT divisible by 10.

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To be divisible by 5, the last digit must be 0 or 5. The last digit of 305 is 5, so it is divisible by 5.

If the last digit is 0 or 5 then the number is divisible by 5. Last digit of 745 is 5 so, 745 is divisible by 5.

no

Any number whose last digit is 0 would be divisible by both these numbers. 1000, 1010, 1020...

Not evenly. You get 43.2 as the answer. To be divisible by 10, the last digit must be 0 The last digit of 432 is 2 which is not 0, so it is not divisible by 10.

Not evenly if you look at the last number and it is an even number such as 2,4,6,8 then it would be evenly divisible by 2.

To be divisible by 5, the last digit must be 0 or 5. The last digit of 28 is neither 0 nor 5, so it is not divisible by 5.

Yes because the last digit is divisible by 2

144 is divisible by 2, 3, 4, 6, 9 and not divisible by 5 or 10.Divisible by 2The whole number is divisible by 2 if the number is even which is shown by the last digit being divisible by 2. The last digit of 144 is 4 and 4 is divisible by 2, thus 144 is divisible by 2.Divisible by 3The number is divisible by 3 if the sum of its digits is also divisible by 3. Sum of the digits of 144 is 1+4+4 = 9 which is divisible by 3, thus 144 is divisible by 3Divisible by 4The number is divisible by 4 is the last two digits is also divisible by 4. Last two digits of 144 are 44 which are divisible by 4, thus 144 is divisible by 4An alternative test: If the last digit plus twice the preceding digit is divisible by 4 then the whole number is divisible by 4.For 144, last digit + twice preceding digit is 4+2x4 = 12 which is divisible by 4, so 144 is divisible by 4Divisible by 5If the last digit is 0 or 5 then the number is divisible by 5 Last digit of 144 is 4 which is neither 0 nor 5, thus 144 is not divisible by 5Divisible by 6To be divisible by 6, the number must be divisible by both of 2 and 3. 144 is divisible by both 2 and 3 (see above), thus 144 is divisible by 6Divisible by 9If the sum of the digits of the number is divisible by 9, then the original number is divisible by 9. For 144, 1+4+4 = 9 which is divisible by 9, thus 144 is divisible by 9Divisible by 10To be divisible by 10, the last digit must be 0. The last digit of 144 is 4 which is not 0, thus 144 is not divisible by 10

All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 926 is a 6 which is NOT a 0, so 936 is NOT divisible by 10.

All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 117 is a 7 which is NOT a 0, so 117 is NOT divisible by 10.

All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 195 is a 5 which is NOT a 0, so 195 is NOT divisible by 10.