4x-5y=20 x-3y=10 becomes x=3y-10 plug that into the first equation: 4(3y-10)-5y=20 12y-40-5y=20 7y=60 y=60/7 If x=3y-10, then x=3(60/7)-10 x=180/7 - 70/7 x=110/7
y=-39
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
The question is not quite clear, do you mean -6x+3y = -18 and -10+5y = -30? If so then the solution is: -10+5y= -30 5y = -30+10 5y = -20 y = -4 Substitute the value of y into the equation -6x+3y = -18: Answer: x = 1 and y = -4
5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
-2 = 3y-18-5y 16=3y-5y 16=-2y y=-8
5 - 2y = 3y - 5 10 = 5y So, y = 2.
no, 4x-3y=11x 3x-5y doesn't equal -11
5y+14+y = 3y-7 5y+y-3y = -7-14 3y = -21 y = -7
3y+5.2=2-5y 8y=-3.2 y= -0.4
(10, 2)
5y - 3y = 18 2y = 18 y = 18/2 y = 9