2x-3y=5 and x-2y=12x-3y+2y=5 and x-2y+2y=12x-y=5 and x=12(1)-y=52-y=52-y-2=5-2-y=3y=-3(x,y) is (1,-3)
For y - 2y - 3y equals 0, y equals 0.
(1, 1)
2y=8..... y=4
15 - 2y = 3y Add 2y to each side to get: 15 = 5y Divide both sides by 5 to get: y = 3 Sorted :-)
5 - 2y = -3y - 2Subtract 5 from each side:-2y = -3y - 7Add 3y to each side:y = -7
3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8
If 3y = 12, 2y = 8
Add the two equations together. The x disappears. 2y - x = 3 + x = 3y - 5 ------------------------ 2y = 3y -2 Can you finish it from there?
2x-3y=5 and x-2y=12x-3y+2y=5 and x-2y+2y=12x-y=5 and x=12(1)-y=52-y=52-y-2=5-2-y=3y=-3(x,y) is (1,-3)
For y - 2y - 3y equals 0, y equals 0.
5y + (4 - 2y) = 9 5y + 4 - 2y = 9 3y + 4 = 9 3y = 5 y = 5/3
5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
3y+5=y-25 2y=-30 y= -15
(1, 1)
2y=8..... y=4
15 - 2y = 3y Add 2y to each side to get: 15 = 5y Divide both sides by 5 to get: y = 3 Sorted :-)