0
when x is a negative number --- is a wrong answer since square root of a negative number is not defined. So x has to be zero or a positive number. The correct answer is that when x lies between 0 and 1 (with both limits excluded), its square root is greater than the number itself. Of course at both limits, the square root (assuming the positive square root - since a square root of a number can be positive or negative, both with the same absolute value) is the same as the number.
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Square root of 98x- square root of -147x square root of 12x?
There is no answer to this problem unless x is 0. For the suare root of 98x to be a real number, x has to be positive or zero. For the square root of -147x to be a real number, x has to be negative or zero. Seeing has x has to fit both requirements, the problem has an answer only if x is zero.
What is the limit as x approaches infinity of the square root of x?
What is the limit as x approaches infinity of the square root of x? Ans: As x approaches infinity, root x approaches infinity - because rootx increases as x does.
What is the square root of X?
Restricting the discussion to real numbers for now. In this case, the square root is only defined for non-negative numbers; the principal square root of a positive number is the POSITIVE square root. For example, both +5 and -5 are square roots of 25, since both - when squared - give you 25. But the positive square root (+5) is called the principal square root, and if you write the square root symbol, that's the number usually meant.
Simplify x divided by the square root of x?
x/x^(1/2)= x^(1/2) or square root of x. When you divide the same base, but with a different exponent, you subtract the exponent of the denominator from that of the numerator.
What is the square root of x to the fourth power?
13
If x is greater than 16 and less than 25 then the square root of x is?
16
For what real numbers is the square root of x greater than x?
For all the values of x that are less than one and greater than zero.
The square root of a number is x is always less than x?
only if x is greater than 1
When is the square root of x greater than zero?
√x > 0 when x > 0, that is when x is a positive number.
Is there an algebraic way to write the square root of x is greater than x?
Sqroot x > x if x<1.
What is the domain for the square root of x minus 3?
it is greater than and equal to 3
Which is greater square root 20 or 10?
10 is greater than square root 20 √20 = √(2 x 10) = √2 x √10 10 = √10 x √10 √10 > √2 → 10 > √20
The square root of X-5 is a real number if and only if?
X is greater than 5. If X were equal to 5, X-5 would be 0 which has no real square root. If X were 4, X-5 would be -1 which has no real square root, and so on.
If x is any real number then why is the square root of x2 not equal to x?
say x=-2, the x^2=4, but the square root of 4 is 2 because we always take the positive value, known as the principal root. Using this square root of x^2=|x|. So if x is greater than or equal 0, than square root of x^2 is x, but if x is less than zero we must take its abolute value.
What could be an example of a function with a domain and a range where a is greater than 0 and b is greater than 0?
f(x) = (x)^ (1/2) (i.e. the square root of x)
The square root of a number x is always less than x?
No. The square roots of numbers between 0 and 1 (not including 0) are greater than or equal to (in the case of 1) the number. The square root of 0.49 is 0.7 for example.
4 is less than the square root of x is less than 9?
x can be any number greater than 16 and less than 81.
