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take x = root 6+ root 6.............upto infinity

x = root 6 + x ........ie take root six once and keep the n number of root 6 as x

square on both sides

x2 = 6 + x

x2 - x- 6 = 0 solve this quadratic equations.

you will get x= 3 or -2

but x is not -2 as it will not satisfy

so x = 3

thus the value

root 6 plus root 6 till infinity = 3

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