What is the limit as x approaches infinity of the square root of x?
Ans: As x approaches infinity, root x approaches infinity - because rootx increases as x does.
The square root of 6 is an irrational number, approximately equal to 2.44948974278. When you take the square root of 6 and continue to do so to infinity, the number will not converge to a specific value but will approach the square root of 6. This means that as you take the square root of the result repeatedly, the number will get closer and closer to approximately 2.44948974278 but will never exactly reach it.
sqrt(x) Domain: {0,infinity) Range: {0,infinity) *note: the domain and range include the point zero.
4x-x^2 \ 2-square root 2 multiply 2+squre root x\ 2+squreroot x = 4x-x^2 (2+squre root x) \ 4_x = x(4-x) (2+squre root x) \ 4-x we will cancel the (4-x) so it will be x(2+squre root x) = (0) (2+squre root 0) =0
The square root of two times the square root of two equals two
81 is the square root and 9.5 is under root.
The sequence sqrt(x)*sin(x) does not converge.
1
Since infinity is not a defined number, it is impossible to have a square root of it. its infinity!
Anawer is Infinity
Infinity
Infinity
infinity is not considered a number it is considered a theory therefore it can not be square rooted
The answer to this whimsical but useless exercise is: Infinity
17.72 + ∞
The answer is infinite.
CoolFunny XDAnd...Smart! Pie = 3.14 The square root of infinity is infinity =|
sqrt(x) Range: {0,infinity)