What is the limit as x approaches infinity of the square root of x?
Ans: As x approaches infinity, root x approaches infinity - because rootx increases as x does.
sqrt(x) Domain: {0,infinity) Range: {0,infinity) *note: the domain and range include the point zero.
take x = root 6+ root 6.............upto infinityx = root 6 + x ........ie take root six once and keep the n number of root 6 as xsquare on both sidesx2 = 6 + xx2 - x- 6 = 0 solve this quadratic equations.you will get x= 3 or -2but x is not -2 as it will not satisfyso x = 3thus the valueroot 6 plus root 6 till infinity = 3
4x-x^2 \ 2-square root 2 multiply 2+squre root x\ 2+squreroot x = 4x-x^2 (2+squre root x) \ 4_x = x(4-x) (2+squre root x) \ 4-x we will cancel the (4-x) so it will be x(2+squre root x) = (0) (2+squre root 0) =0
The square root of two times the square root of two equals two
81 is the square root and 9.5 is under root.
The sequence sqrt(x)*sin(x) does not converge.
1
Since infinity is not a defined number, it is impossible to have a square root of it. its infinity!
Anawer is Infinity
Infinity
Infinity
infinity is not considered a number it is considered a theory therefore it can not be square rooted
The answer to this whimsical but useless exercise is: Infinity
17.72 + ∞
The answer is infinite.
CoolFunny XDAnd...Smart! Pie = 3.14 The square root of infinity is infinity =|
sqrt(x) Range: {0,infinity)