If the function is to be continuous, then it is a function if
x3 + 2 ≤ 0 or if x3 + 2 ≥ 0 but not both.
That is, when x3 ≤ -2 or x3 ≥ -2.
So x ≤ -1.2599 or x ≥ -1.2599 (approx).
The graph is like a parabola that has been tipped on its side and the above procedure takes either the top half of the parabola or the bottom half. That way you can be sure that no vertical line intersects the graph in more than one place. However, that can also be achieved by taking a segment of the curve above the x-axis, then the next segment from below, then above and below and so on.
y2=x3+3x2
Yes
2x2-y2
Yes, as x-y2=0
(x2 - xy + y2)(x + y)
y = kx3/2If y2 varies directly with x3, then y varies directly with sqrt(x3) or x3/2.Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. If your question is not answered, please resubmit it, spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (x^2) or x-squared. :-)
(2-r)e-rr
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
yes that is correct
No.
7
x2 + y2 = 2r2