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Q: When was X. B. Saintine born?

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X. B. Saintine died in 1865.

(x - a) + (x - a) + (b) = 2 (x - a) + (b) = x - a + x - a + b = 2x - 2a + b

A condensed form of a * a * b * b * b is a2 * b3.a * a * b * b * b = a2 * b3

a2b3

x^a / x^b = x^(a-b)andx^a * x^b = x^(a+b)

X^â x X^b= x^â+b x^a divided by x^b = x^a+b (x^a)^b=x^ab x^0=1 x^-a=1/x^a

[a, b] : a â‰¤ x â‰¤ b [a, b) : a â‰¤ x < b (a, b] : a < x â‰¤ b (a, b) : a < x < b

15a4b2 = 3 x 5 x a x 2 x 2 x b x b35a3b6 = 5 x 7 x a x 3 x b x b x b x b x b x bSo, Greatest Common Factor = 5 x a x b x b = 5ab2

It must be x*(x+1). To see this, suppose that there existed a smaller common multiple formed by taking a*x and b*(x+1), where a =/= b since multiplying by the same number won't give you a common multiple. Then we have a*x < x*(x+1) => a < (x+1) b*(x+1) < x*(x+1) => b < x => a*b < x*(x+1). Also, a*x = b*(x+1) => x = b/(a-b) & (x+1) = a/(a-b). Therefore x*(x+1) = a*b/(a-b)^2 < x*(x+1)/(a-b)^2 => (a-b)^2 < 1 => (a-b) < 1. The problem here is that this requires that a=b, which cannot be. Therefore, x*(x+1) is the smallest common multiple of both x and (x+1)

b4

16B3 = 2 x 2 x 2 x 2 x B x B x B24B4 = 2 x 2 x 2 x 3 x B x B x B x BGreatest Common Factor = 2 x 2 x 2 x 2 x B x B x B = 8B3

a x a x a x a x b = a4b

The derivative of e^u(x) with respect to x: [du/dx]*[e^u(x)]For a general exponential: b^x, can be rewritten as b^x = e^(x*ln(b))So derivative of b^x = derivative of e^u(x), where u(x) = x*ln(b).Derivative of x*ln(b) = ln(b). {remember b is just a constant, so ln(b) is a constant}So derivative of b^x = ln(b)*e^(x*ln(b))= ln(b) * b^x(from above)

Misha B sang Born this way

Let x be in A intersect B. Then x is in A and x is in B. Then x is in A.

Factor them. 2 x 2 x b x b = 4b2 2 x 3 x b x b x b = 6b3 Combine the factors, eliminating duplicates. 2 x 2 x 3 x b x b x b = 12b3, the LCM

2 x a x a x a x a x b x b x b = 2a4b3

2 x a x a x a x a x b x b x b

There are many methods. A simple way to test that X lies between A and B isIf (A-X)*(B-X) is negative then X lies between them.If (A-X)*(B-X) is positive then X does not lie between them.If (A-X)*(B-X) is zero then X = A or X = B.There are many methods. A simple way to test that X lies between A and B isIf (A-X)*(B-X) is negative then X lies between them.If (A-X)*(B-X) is positive then X does not lie between them.If (A-X)*(B-X) is zero then X = A or X = B.There are many methods. A simple way to test that X lies between A and B isIf (A-X)*(B-X) is negative then X lies between them.If (A-X)*(B-X) is positive then X does not lie between them.If (A-X)*(B-X) is zero then X = A or X = B.There are many methods. A simple way to test that X lies between A and B isIf (A-X)*(B-X) is negative then X lies between them.If (A-X)*(B-X) is positive then X does not lie between them.If (A-X)*(B-X) is zero then X = A or X = B.

a*x% = b or a*x/100 = b

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x=b-a

It is A A A B B B Y X Y X B L+R X

Associative: (a + b) + c = a + (b + c) (a x b) x c = a x (b x c)

(a x b) x c = a x (b x c)