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Where are the points of intersection of the parabolas y equals plus 4x squared -2x -1 and y equals -2x squared plus 3x plus 5 on the Cartesian plane showing details of work?
Wiki User
∙ 10y ago
If: y = 4x2-2x-1 and y = -2x2+3x+5
Then: 4x2-2x-1 = -2x2+3x+5
And so: 6x2-5x-6 = 0
Using the the quadratic equation formula: x = -2/3 and x = 3/2
Substitution: when x = -2/3 then y = 19/9 and when x = 3/2 then y = 5
Points of intersection: (-2/3, 19/9) and (3/2, 5)
Wiki User
∙ 10y ago
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What are the points of intersection of the parabolas y equals 4x squared -2x -1 and y equals -2x squared plus 3x plus 5 showing work with answers?
If: y = 4x^2 -2x -1 and y = -2x^2 +3x +5 Then: 4x^2-2x-1 = -2x^2+3x+5 =>6x^2-5x-6 = 0 Solving the above quadratic equation: x = -2/3 or x = 3/2 Therefore by substitution the points of intersection are: (-2/3, 19/9) and (3/2, 5)
What are the points of intersection of the parabolas y equals 4x squared -2x -1 and y equals -2x squared plus 3x plus 5 showing work and answers?
If: y = 4x^2 -2x -1 and y = -2x^2+3x+5 Then: 4x^2 -2x -1 = -2x^2+3x+5 => 6x^2-5x-6 = 0 Solving the above quadratic equation: x = -2/3 or x = 3/2 Therefore the points of intersection by substitution are: (-2/3, 19/9) and (3/2, 5)
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