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If: y = 4x2-2x-1 and y = -2x2+3x+5
Then: 4x2-2x-1 = -2x2+3x+5
And so: 6x2-5x-6 = 0
Using the the quadratic equation formula: x = -2/3 and x = 3/2
Substitution: when x = -2/3 then y = 19/9 and when x = 3/2 then y = 5
Points of intersection: (-2/3, 19/9) and (3/2, 5)
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What is the point of intersection of the parabolas y equals x2 plus 20x plus 100 and y equals x2 -20x plus 100 showing work?
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
What is if any are the points of intersection of the parabolas y equals x2 -4x plus 8 and y equals 8x -x2 -14 showing work with explanations?
If: y = x2-4x+8 and y = 8x-x2-14 Then: x2-4x+8 = 8x-x2-14 So: 2x2-12x+22 = 0 Discriminant: 122-(4*2*22) = -32 Because the discriminant is less than 0 there is no actual contact between the given parabolas
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What are the points of intersection of the parabolas y equals 4x squared -2x -1 and -2x squared plus 3x plus 5 showing key stages of work?
If: y = 4x2-2x-1 and y = -2x2+3x+5 Then: 4x2-2x-1 = -2x2+3x+5 So: 6x2-5x-6 = 0 Solving the quadratic equation: x = -2/3 or x = 3/2 Points of intersection by substitution: (-2/3, 19/9) and (3/2, 5)
What is the point of intersection of the equation 4y equals 5x with the line joining the points 13 17 and 19 23 on the Cartesian plane showing work?
Points of line: (13, 17) and (19, 23) Its slope: 1 Its equation: y = x+4 => y-x = 4 Multiply all terms by 4: 4y-4x = 16 Equation of: 4y = 5x => 4y-5x = 0 Subtacting equations: x = 16 By substitution point of intersection is at: (16, 20)
What are the points of intersection of the line 2x plus y equals 5 with x squared minus y squared equals 3 on the Cartesian plane showing work?
Improved Answer:-If: 2x+y = 5 and x^2 -y^2 = 3Then by rearranging: y = 5 -2x and -3x^2 -28+20x = 0Solving the above quadratic equation: x = 2 and x = 14/3By substitution points of intersection are: (2, 1) and (14/3, -13/3)
What are the points of intersection of the parabolas when y equals -2x squared plus 3x plus 5 and y equals 4x squared -2x -1 showing work?
If: y = -2x^2 +3x +5 and y = 4x^2 -2x -1 Then: 4x^2 -2x -1 = -2x^2 +3x +5 So it follows: 6x^2 -5x -6 = 0 Using the quadratic equation formula: x = -2/3 or x = 3/2 Therefore points of intersection by substitution are at: (-2/3, 19/9) and (3/2, 5)
What are the points of intersection of the parabolas y equals 4x squared -2x -1 and y equals -2x squared plus 3x plus 5 showing work with answers?
If: y = 4x^2 -2x -1 and y = -2x^2 +3x +5 Then: 4x^2-2x-1 = -2x^2+3x+5 =>6x^2-5x-6 = 0 Solving the above quadratic equation: x = -2/3 or x = 3/2 Therefore by substitution the points of intersection are: (-2/3, 19/9) and (3/2, 5)
What are the points of intersection of the parabolas y equals 4x squared -2x -1 and y equals -2x squared plus 3x plus 5 showing work and answers?
If: y = 4x^2 -2x -1 and y = -2x^2+3x+5 Then: 4x^2 -2x -1 = -2x^2+3x+5 => 6x^2-5x-6 = 0 Solving the above quadratic equation: x = -2/3 or x = 3/2 Therefore the points of intersection by substitution are: (-2/3, 19/9) and (3/2, 5)
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taking or showing extreme care about minute details
What is the perpendicular distance from the point of 2 4 on the Cartesian plane to the straight line equation of y equals 2x plus 10 showing key stages of work?
1 Equation: y = 2x+10 2 Perpendicular equation works out as: 2y = -x+10 3 Point of intersection: (-2, 6) 4 Distance is the square root of: (-2-2)2+(6-4)2 = 2 times sq rt of 5
