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So by definition both equations equal one another:

5x2-2x+1 = 6-3x-x2

5x2+x2-2x+3x+1-6 = 0

6x2+x-5 = 0

Factor the above equation with the help of the quadratic equation formula:

(6x-5)(x+1) = 0

When x = -1 y = 8

When x = 5/6 y = 101/36

Therefore the curves intersect at points: (-1, 8) and (5/6, 101/36)

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Q: Where are the points of intersection on the curves y equals 5x squared minus 2x plus 1 and y equals 6 minus 3x minus x squared?
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