There are two simultaneous equations to solve:
The second can be rearranged to make x the subject, substituted into the first and the values of y found:
y² = x + 4 → x = y² - 4
2x + 5y = 4
→ 2(y² -4) + 5y = 4
→ 2y² -8 + 5y - 4 = 0
→ 2y² +5y - 12 = 0
→ (2y - 3)(y + 4) = 0
→ y = 1½ or -4
These values can be substituted into either equation to find the value of x; I'll use the second:
y² = x + 4
→ x = y² - 4
The two solutions are (x, y) = (-0.5, -sqrt(3.5)) and (-0.5, sqrt(3.5))
Points of intersection work out as: (3, 4) and (-1, -2)
If: y = x2-x-12 Then points of contact are at: (0, -12), (4, 0) and (-3, 0)
The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.
5.477225575 squared equals 30.
The two solutions are (x, y) = (-0.5, -sqrt(3.5)) and (-0.5, sqrt(3.5))
It is the Cartesian equation of an ellipse.
Points of intersection work out as: (3, 4) and (-1, -2)
If: y = x2-x-12 Then points of contact are at: (0, -12), (4, 0) and (-3, 0)
It is (-0.3, 0.1)
Equations: y = x+4 and x^2 +y^2 -8x +4y = 30 The given equations will finally form a quadratic equation such as: x^2 +2x +1 = 0 Discriminant: 2^2 -4*(1*1) = 0 meaning there are equal roots Because the discriminant has equal roots the line is a tangent to the circle In fact the line makes contact with the circle at (-1, 3) on the Cartesian plane
5.477225575 squared equals 30.
The number that equals 121 when squared is 11.
The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.
b = sqrt32 or 4 root 2
No, it equals -2xy. lrn2math
It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)